我的输入XML文件
<employerinfo id="2242">
<Employer>
<Employeedetail>Sam SR Engineer 10%</Employeedetail>
<Employeedetail>Sam SR 26%</Employeedetail>
<Employeedetail>Sam SR</Employeedetail>
<Employeedetail>Sam GRTE</Employeedetail>
</Employer >
</employerinfo>
预期输出文件
<Employer>
<Employeedetails>
<Employeedetail1>
<Employeedetail>
<Name>Sam</Name>
<Grade>SR Engineer</Grade>
<Experience>10</Experience>
</Employeedetail>
<Employeedetail>
<Name>Sam</Name>
<Grade>SR</Grade>
<Experience>26</Experience>
<Employeedetail>
<Name>Sam</Name>
<Grade>SR</Grade>
<Experience>10</Experience>
</Employeedetail>
<Employeedetail>
<Name>Sam</Name>
<Grade>GRTE</Grade>
<Experience>10</Experience>
</Employeedetail >
</Employeedetail1>
</Employeedetails>
</Employer>
我尝试在Google中搜索这种类型的XML如何在xslt 1.0&amp; xslt 2.0
其他几个Stack Overflow用户也对我有所帮助。但这仍然是最终的细节输入XML。
如果我在XML中添加了额外的父节点,并且如果我在XSLT中修改了我没有得到值
请帮帮我
提前致谢
答案 0 :(得分:0)
到目前为止,这是我的解决方案:
<?xml version='1.0' encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
version='1.0'
>
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:template match="Employer">
<Employer>
<Employeedetails>
<Employeedetail1>
<xsl:apply-templates select="Employeedetail"/>
</Employeedetail1>
</Employeedetails>
</Employer>
</xsl:template>
<xsl:template match="Employeedetail">
<Employeedetail>
<xsl:variable name="s1" select="normalize-space(.)"/>
<xsl:variable name="name" select="substring-before($s1,' ')"/>
<Name><xsl:value-of select="$name"/></Name>
<xsl:variable name="s2" select="substring-after($s1,' ')"/>
<xsl:call-template name="t">
<xsl:with-param name="s" select="$s2"/>
<xsl:with-param name="grade"></xsl:with-param>
<xsl:with-param name="exp"></xsl:with-param>
</xsl:call-template>
</Employeedetail>
</xsl:template>
<xsl:template name="t">
<xsl:param name="s"/>
<xsl:param name="grade"/>
<xsl:param name="exp"/>
<xsl:choose>
<xsl:when test="contains($s,' ')">
<xsl:call-template name="t">
<xsl:with-param name="s" select="substring-after($s,' ')"/>
<xsl:with-param name="grade"><xsl:value-of select="$grade"/><xsl:text> </xsl:text><xsl:value-of select="substring-before($s,' ')"/></xsl:with-param>
<xsl:with-param name="exp"><xsl:value-of select="substring-after($s,' ')"/></xsl:with-param>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:choose>
<xsl:when test="string-length($exp)>0">
<Grade><xsl:value-of select="normalize-space($grade)"/></Grade>
<Experience><xsl:value-of select="$exp"/></Experience>
</xsl:when>
<xsl:otherwise>
<Grade><xsl:value-of select="normalize-space($s)"/></Grade>
<Experience>10</Experience>
</xsl:otherwise>
</xsl:choose>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
结果:
<Employer>
<Employeedetails>
<Employeedetail1>
<Employeedetail>
<Name>Sam</Name>
<Grade>SR Engineer</Grade>
<Experience>10%</Experience>
</Employeedetail>
<Employeedetail>
<Name>Sam</Name>
<Grade>SR</Grade>
<Experience>26%</Experience>
</Employeedetail>
<Employeedetail>
<Name>Sam</Name>
<Grade>SR</Grade>
<Experience>10</Experience>
</Employeedetail>
<Employeedetail>
<Name>Sam</Name>
<Grade>GRTE</Grade>
<Experience>10</Experience>
</Employeedetail>
</Employeedetail1>
</Employeedetails>
</Employer>
答案 1 :(得分:0)
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:output indent="yes" omit-xml-declaration="yes"/>
<xsl:template match="Employer">
<Employer>
<Employeedetails>
<Employeedetail1>
<xsl:apply-templates/>
</Employeedetail1>
</Employeedetails>
</Employer>
</xsl:template>
<xsl:template match="Employeedetail">
<xsl:analyze-string select="." regex="^(.*) ((SR|GR).*?)( ([0-9]+)%)?$">
<xsl:matching-substring>
<Employeedetail>
<Name><xsl:value-of select="regex-group(1)"/></Name>
<Grade><xsl:value-of select="regex-group(2)"/></Grade>
<Experience><xsl:value-of select="if(regex-group(5)) then regex-group(5) else 10"/></Experience>
</Employeedetail>
</xsl:matching-substring>
</xsl:analyze-string>
</xsl:template>
</xsl:stylesheet>