Question

我的视图 - 控制器关系存在这个问题。这是控制器：

<?php
class AnswersController extends AppController {
    public $helpers = array('Html', 'Form', 'Session');
    public $components = array('Session');

    public function add() {

        $customer_id = $this->params['url']['customer_id'];
        $question_set_id = $this->params['url']['question_set_id'];
        $order_value = $this->params['url']['order_value'];

        $possible_answer_model = ClassRegistry::init('PossibleAnswer');
        $question_model = ClassRegistry::init('Question');
        $order_model = ClassRegistry::init('Order');

        $order = $order_model -> find('first', array(
        'Order.question_set_id' => $question_set_id,
        'Order.value' => $order_value));

        $question = $question_model -> find('first', array(
        'Question.id' => $order['Order']['question_id']));

        $this -> set('question', $question);

        if ($question['Question']['kind'] != "o") {
            $this -> set('possible_answers', $possible_answer_model -> find('all', array(
            'PossibleAnswer.question_id' => $question['Question']['id'])));
        }

        $this->Session->setFlash($question['Question']['content']);
    }
}

它得到了正确的问题和possible_answers（我可以看到查询输出），但视图总是显示相同的问题（无论我将传递给action的什么question_set_id和order_value）和所有的possible_answers（不仅仅是这些这实际上与问题有关，即使这个问题总能表现出来。由于查询输出正确，我想将数据传递给视图需要遇到一些问题。无论如何，视图看起来像这样：

<!-- File: /app/View/Answers/add.ctp -->

<?php
if ($question['Question']['kind'] == 'o') {
    echo $this->Form->create('PossibleAnswer');
    echo $this->Form->input('content', array(
    'rows' => '3', 'label' => 'Miejsce na twoją odpowiedź:'));
    echo $this->Form->input('PossibleAnswer', array(
    'question_id' => $question['Question']['id']));
    echo $this->Form->end('Dalej');
}
else {
    echo $this->Form->create('Answer');
    foreach ($possible_answers as $possible_answer) {
        echo '<input name="'
        .'possible_answers'
        .'" id="'
        .$possible_answer['PossibleAnswer']['id']
        .'" value="'
        .$possible_answer['PossibleAnswer']['id']
        .'" type="radio">';
        echo '<label for="'
        .$possible_answer['PossibleAnswer']['id']
        .'">'
        .$possible_answer['PossibleAnswer']['content']
        .'</label><br />';
    }
    echo $this->Form->end('Dalej');
}
?>

，查询输出如下：

1 SELECT Order。id，Order。question_id，Order。question_set_id，Order。{{1 }，value。Question，id。Question，content。Question，company_id。Question ，kind。QuestionSet，id。QuestionSet，name。QuestionSet FROM company_id。mentor11 AS { {1}} LEFT JOIN orders。Order AS mentor11 ON（questions。Question = Order。question_id）LEFT加入Question。id AS mentor11 ON（question_sets。QuestionSet = Order。question_set_id）WHERE 1 = 1 LIMIT 1

（受影响的1，数量为1行，为25）

2 SELECT QuestionSet。id，Question。id，Question。content，Question。{{1 }，company_id。Question，kind。Company，id。Company FROM trader_id。Company AS name LEFT JOIN mentor11。questions AS Question ON（mentor11。companies = Company。Question ）WHERE 1 = 1 LIMIT 1

（受影响的1，数量为1行，为49）

3 SELECT company_id。Company，id。Order，id。Order，question_id。{{1 } {FROM} Order。question_set_id AS Order WHERE value。mentor11 =（1）

（受影响的1，数字行1，花了28）

4 SELECT orders。Order，Order。question_id，PossibleAnswer。id FROM PossibleAnswer。{{1 AS content WHERE PossibleAnswer。question_id =（1）

（受影响的2，数量为2行，为35）

5 SELECT mentor11。possible_answers，PossibleAnswer。PossibleAnswer，question_id。PossibleAnswer FROM id。{{1 AS PossibleAnswer WHERE 1 = 1

（受影响5，数量5行，需要23次）

正如您所看到的，第4个查询返回两个可能的答案，但视图中包含其中的五个（现在它们全部都是）： view

起初我怀疑第5个查询（返回所有的possible_answers）以某种方式“删除”第4个查询;我仍然不知道第五个查询是如何被调用的（我不需要它，我可以看到没有一段代码可以调用这样的查询）但我将“my”$ possible_answers更改为$ possible_answerz只是为了使它成为可能不同 - 它没有用，但即使它确实如此：它也无法解释为什么$问题总是一样的......

任何提示？

编辑：当我刷新值时 - 它们是正确的......

Answer 1

试试这个：

$order = $order_model -> find('first', array(
    'conditions' => array(
        'Order.question_set_id' => $question_set_id,
        'Order.value' => $order_value)
    )
);

然后将'conditions'键添加到其他数组

CakePHP并将变量从控制器发送到视图

1 个答案: