Question

当我运行我的Python应用程序（在本地同步远程目录）时，如果包含我的应用程序的目录在其名称中有一个或多个空格，则会出现问题。目录名称显示在“-o UserKnownHostsFile=<path>”和“-i <path>”等ssh选项中。我尝试在我的函数中引用生成命令字符串的路径，但没有。我也尝试替换这样的空格：path.replace(' ', '\\ ')，但它不起作用。请注意，我的代码使用没有空格的dirnames。 ssh返回的错误是“行尾的垃圾”（代码12）生成的命令行似乎没问题。

rsync -rztv --delete --stats --progress --timeout=900 --size-only --dry-run \
    -e 'ssh -o BatchMode=yes \
    -o UserKnownHostsFile="/cygdrive/C/Users/my.user/my\ app/.ssh/known_hosts" \
    -i "/cygdrive/C/Users/my.user/my\ app/.ssh/id_rsa"'
    user@host:/home/user/folder/ "/cygdrive/C/Users/my.user/my\ app/folder/"

我做错了什么？谢谢！

Answer 1

您是否尝试将命令构建为参数列表 - 我在传递ssh连接的密钥文件时遇到了类似的问题：

command = [
  "rsync",
  "-rztv",
  "--delete",
  "--stats",
  "--progress",
  "--timeout=900",
  "--size-only",
  "--dry-run",
  "-e",
  "ssh -o BatchMode=yes -o UserKnownHostsFile='/cygdrive/C/Users/my.user/my\ app/.ssh/known_hosts' -i '/cygdrive/C/Users/my.user/my\ app/.ssh/id_rsa'",
  "user@host:/home/user/folder/",
  "/cygdrive/C/Users/my.user/my\ app/folder/"
]

sp = subprocess.Popen(command, shell=True, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
output = sp.communicate()[0]

Answer 2

子命令返回的数据包括空格作为分隔符。尝试更新内部字段分隔符（IFS）列表，如：

# store a copy of the current IFS
SAVEIFS=$IFS;
# set IFS to be newline-only
IFS=$(echo -en "\n\b");

# execute your command(s)
rsync -rztv --delete --stats --progress --timeout=900 --size-only --dry-run -e 'ssh -o BatchMode=yes -o UserKnownHostsFile="/cygdrive/C/Users/my.user/my\ app/.ssh/known_hosts" -i "/cygdrive/C/Users/my.user/my\ app/.ssh/id_rsa"' user@host:/home/user/folder/ "/cygdrive/C/Users/my.user/my\ app/folder/"

# put the original IFS back
IFS=$SAVEIFS;

我没有使用你的命令进行测试，虽然它在我过去尝试的所有情况下都有效。

Answer 3

为避免转义问题，请使用原始字符串

raw_string = r'''rsync -rztv --delete --stats --progress --timeout=900 --size-only --dry-run -e 'ssh -o BatchMode=yes -o UserKnownHostsFile="/cygdrive/C/Users/my.user/my app/.ssh/known_hosts" -i "/cygdrive/C/Users/my.user/my app/.ssh/id_rsa"' user@host:/home/user/folder/ "/cygdrive/C/Users/my.user/my app/folder/"'''

sp = subprocess.Popen(raw_string, shell=True, stdout=subprocess.PIPE, stderr=subprocess.STDOUT)
output = sp.communicate()[0]

python子进程中的rsync + ssh使用目录名中的空格获取错误

3 个答案: