Question

我在Hypertable中插入了数据。但我不知道，如何从结果中获得特定的价值。我的PHP thrift代码是：

    $GLOBALS['THRIFT_ROOT'] = "/opt/hypertable/0.9.5.6/lib/php";

    require_once $GLOBALS['THRIFT_ROOT'].'/ThriftClient.php';

    $client = new Hypertable_ThriftClient("localhost", 38080);

    $namespace = $client->namespace_open("appuniv");

    $query = "select * from category_details limit 1";

    $tab = $client->hql_query($namespace, $query);

    var_dump($tab);

我得到以下结果：

object（Hypertable_ThriftGen_HqlResult）＃24（4）{[“results”] =＆gt;空值 [ “细胞”] =＆GT; array（2）{[0] =＆gt;对象（Hypertable_ThriftGen_Cell）＃25（2） {[“key”] =＆gt; object（Hypertable_ThriftGen_Key）＃26（6）{[“row”] =＆gt; string（32）“077262cc53a1fb1b5f651d31b6bf81ba”[“column_family”] =＆gt; string（8）“category”[“column_qualifier”] =＆gt; string（4）“name” [ “时间戳”] =＆GT; float（1.3419935154984E + 18）[“revision”] =＆gt; float（1.3419935154984E + 18）[“flag”] =＆gt; int（255）} [“value”] =＆gt;串（7） “医疗”} [1] =＆gt; object（Hypertable_ThriftGen_Cell）＃27（2）{[“key”] =＆gt; object（Hypertable_ThriftGen_Key）＃28（6）{[“row”] =＆gt;串（32） “077262cc53a1fb1b5f651d31b6bf81ba”[“column_family”] =＆gt;串（8） “category”[“column_qualifier”] =＆gt; string（4）“type”[“timestamp”] =＆gt; float（1.3419935154984E + 18）[“revision”] =＆gt;浮子（1.3419935154984E + 18） [ “标志”] =＆GT; int（255）} [“value”] =＆gt; string（7）“android”}} [ “扫描器”] =＆GT; NULL [“mutator”] =＆gt; NULL} 0.9678

我可以知道如何获得 [“value”] =＆gt; string（7）来自上述结果的“医疗”值。

Answer 1

/**
 * Sort result by column family/qualifier
 * @param thrift result
 */
private function sort($data)
{
    $result = array();
    foreach ($data as $cell)
    {
        $row = $cell->key->row;
        if (!isset($result[$row])) {
            $result[$row] = new stdClass;
            $result[$row]->row = $cell->key->row;
            foreach ($this->columns as $col) {
                $pos = strpos($col, ':') ;
                $qualifier = ($pos) ? substr($col, $pos + 1) : NULL;
                $col = !$pos ? $col : substr($col, 0, $pos);
                if (!$qualifier)
                    $result[$row]->{$col} = NULL;
                else if ($qualifier[0] != '/')
                    $result[$row]->{$col}[$qualifier] = NULL;
            }
        }
        $result[$row]->{$cell->key->column_family}[$cell->key->column_qualifier] = $cell->value;
    }
    return $result;
}

如何使用php解析Hypertable数据

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