我坚持这个问题。数据库架构由其他人提供,所以我不能简单地更改名称。我尝试添加适当的注释,也许我错过了一些东西(显而易见)?
这是我的完整映射(很多classess),我会省略getter / setters。
问题是当hibernate试图获得所有List<ControlRuleAttrib> controlRuleAttribs
控制规则
@Entity
@Table(name = "CONTROL_RULE")
public class ControlRule implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "CONTROL_RULE_ID")
private Long id;
@ManyToOne(fetch = FetchType.LAZY)
@Cascade(CascadeType.ALL)
@JoinColumn(name = "CONTROL_RULE_TYPE_ID")
@ForeignKey(name = "CONTROL_RULE_TYPE_ID")
private ControlRuleType controlRuleType;
@Column(name = "JOB_NM")
private String jobname;
@Column(name = "LIBRARY_NM")
private String libraryname;
@Column(name = "TABLE_NM")
private String tablename;
@Column(name = "COLUMN_NM")
private String columnname;
@OneToMany(fetch = FetchType.LAZY)
@Cascade(CascadeType.ALL)
@JoinTable(name = "CONTROL_RULE_ATTRIB", joinColumns = {
@JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)
})
private List < ControlRuleAttrib > controlRuleAttribs;
}
ControlRuleAttrib
@Table(name = "CONTROL_RULE_ATTRIB")
@Entity
public class ControlRuleAttrib {
@EmbeddedId
private ControlRuleAttribPK controlRuleAttribPK;
@Column(name = "ATTRIBUTE_VALUE")
private String attributeValue;
}
ControleRuleAttribPK
这里的问题是,是否有可能以某种方式从ControlRuleAttribType
获取实体ControlRuleAttrib
?正如您在下面看到的,ControlRuleAttribTypeId
是ControleRuleAttribType
的ID。我想得到整个对象isteand的整数。
@Embeddable
public class ControlRuleAttribPK implements Serializable {
@Column(name = "CONTROL_RULE_ID")
private Long controlRuleId;
@Column(name = "ATTRIBUTE_SEQ_NUM")
private Integer attributeSeqNum;
@Column(name = "CONTROL_RULE_ATTRIB_TYPE_ID")
private Integer controlRuleAttribTypeId;
}
ControleRuleAttribType
@Entity
@Table(name = "CONTROL_RULE_ATTRIB_TYPE")
public class ControlRuleAttribType implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "CONTROL_RULE_ATTRIB_TYPE_ID")
private Integer id;
@Column(name = "CONTROL_RULE_ATTRIB_TYPE_NM")
private String typename;
@Column(name = "CONTROL_RULE_ATTRIB_TYPE_DESC")
private String typedesc;
@ManyToOne(fetch = FetchType.LAZY)
@Cascade(CascadeType.ALL)
@JoinColumn(name = "CONTROL_RULE_TYPE_ID")
@ForeignKey(name = "CONTROL_RULE_TYPE_ID")
private ControlRuleType controlruletype;
}
ControleRuleType
@Entity
@Table(name = "CONTROL_RULE_TYPE")
public class ControlRuleType implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Column(name = "CONTROL_RULE_TYPE_ID")
private Integer id;
@Column(name = "CONTROL_RULE_TYPE_NM")
private String typename;
@Column(name = "CONTROL_RULE_TYPE_DESC")
private String typedesc;
}
修改
这是stacktrace:
https://gist.github.com/a30dd9ce534d96bb9a97
你会发现,它在这里失败了:
在 com.execon.controllers.main.MainPageController.getMainPage(MainPageController.java:33) [类:
就是这样:
List<ControlRule> list = SessionFactoryUtils.openSession(
sessionFactory ).createQuery( "from ControlRule" ).list();
System.out.println( list );
我添加的映射的每个对象都有toString()
方法声明如下:
@Override
public String toString()
{
String s = "ControlRule{";
s += "id=" + id.toString();
s += ", controlRuleType=" + controlRuleType;
s += ", jobname='" + jobname + '\'';
s += ", libraryname='" + libraryname + '\'';
s += ", tablename='" + tablename + '\'';
s += ", columnname='" + columnname + '\'';
s += ", controlRuleAttribs=" + controlRuleAttribs;
s += '}';
return s;
}
和hibernate请求:
https://gist.github.com/c8584113522757a4e0d8/4f31dc03e7e842eef693fa7ba928e19d27b3ca26
请帮助:)
编辑2
在阅读@Jens回答之后,我对代码进行了一些更改。首先,我按照你的写作做了,它给出了错误:
org.hibernate.AnnotationException:外键引用 来自的com.execon.models.controlrules.ControlRuleAttrib com.execon.models.controlrules.ControlRule的编号错误 柱。应该是3
我想这是对的,因为我有复合主键。
然后我就这样试了:
@OneToMany(fetch = FetchType.LAZY)
@Cascade(CascadeType.ALL)
@JoinTable(name = "CONTROL_RULE_ATTRIB",
joinColumns = {
@JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)
},
inverseJoinColumns = {
@JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false),
@JoinColumn(name = "CONTROL_RULE_ATTRIB_TYPE_ID", nullable = false, updatable = false),
@JoinColumn(name = "ATTRIBUTE_SEQ_NUM", nullable = false, updatable = false)
})
private List<ControlRuleAttrib> controlRuleAttribs;
非常接近,但它给了我以下例外:
映射集合中的重复列..
所以最后我删除了
joinColumns =
{
@JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)
}
除了当我尝试访问集合时,Hibernate正在进行以下查询:
https://gist.github.com/c88684392f0b7a62bea5
最后一行是controlrul0_.CONTROL_RULE_CONTROL_RULE_ID=?
,而应该是controlrul0_.CONTROL_RULE_ID=?
。
无论如何我能使它运作吗? :/
答案 0 :(得分:2)
在最近几个小时的努力之后,我终于让它在我的项目中工作了。我做的是这个:
<强> ControlRule 强>
@OneToMany(fetch = FetchType.LAZY, mappedBy = "controlRuleAttribPK.controlRuleId")
@Cascade(CascadeType.ALL)
private List<ControlRuleAttrib> controlRuleAttribs;
基本上指出集合应该使用复合主键中的controlRuleId。到目前为止它的工作很棒!
答案 1 :(得分:0)
我不清楚哪个标识符太长,但我建议您可以尝试将@Id
带注释的字段类型从Integer
更改为Long
。获得有关您问题的详细信息(堆栈跟踪等)会很棒。
答案 2 :(得分:0)
问题是专栏
CONTROL_RULE_ATTRIB.controlRuleAttribs_CONTROL_RULE_ATTRIB_TYPE_ID
这是多久,它不可能存在于您的数据库中。我没有在问题中看到它是如何实际命名的,但我假设正确的名称是
CONTROL_RULE_ATTRIB.CONTROL_RULE_ATTRIB_TYPE_ID
所以问题是:为什么hibernate试图访问这个列。它所在的表是一个映射表,它在hibernate中映射为:
@OneToMany(fetch = FetchType.LAZY)
@Cascade(CascadeType.ALL)
@JoinTable(name = "CONTROL_RULE_ATTRIB", joinColumns = {@JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)})
private List<ControlRuleAttrib> controlRuleAttribs;
如果查看@JoinTable注释,您会注意到它定义了使用的表名和连接列。但是映射表有两组连接列。第二个未指定。因此,使用您配置的NamingStrategy或未配置任何默认值的NamingStrategy。只需使用属性inverseJoinColumns指定另一组连接列,所有都应该没问题。
完整注释应如下所示:
@JoinTable(name = "CONTROL_RULE_ATTRIB", joinColumns = {@JoinColumn(name = "CONTROL_RULE_ID", nullable = false, updatable = false)}, inverseJoinColumns = {@JoinColumn(name = "CONTROL_RULE_ATTRIB_TYPE_ID")})
注意:我不知道你是否需要该列上任何可以为空的可更新内容。