我将linq结果数据绑定到datagrid但没有任何结果。这是我的代码
List<SearchResult> list = new List<SearchResult>() {
new SearchResult(){ID=1,Title="Geo Prism 1995 GEO* - ABS #16213899"},
new SearchResult(){ID=2,Title="Excavator JCB - ECU P/N: 728/35700"},
new SearchResult(){ID=3,Title="Geo Prism GEO 1995 - ABS #16213899"},
new SearchResult(){ID=4,Title="JCB Excavator JCB- ECU P/N: 728/35700"},
new SearchResult(){ID=5,Title="Geo Prism GEO,GEO 1995 - ABS #16213899 GEO"},
new SearchResult(){ID=6,Title="dog"},
};
var to_search = new[] { "Geo", "JCB" }.Select(x => x.ToLower()).ToArray();
var result = from searchResult in list
let title = searchResult.Title.ToLower()
let key_string = to_search.FirstOrDefault(ts => title.Contains(ts))
orderby key_string == null ? -1 : title.Split(new[] { key_string }, StringSplitOptions.None).Length descending
group searchResult by key_string into Group
orderby Group.Count() descending
select Group;
dataGridView2.DataSource = result;
当我运行上面的代码时,datagrid显示什么,但我期待datagrid应显示 ID和标题
然后我添加一些像
这样的行List<SearchResult> listFinal = new List<SearchResult>();
foreach (var group in result)
{
foreach (var item in group)
{
listFinal.Add(new SearchResult() { ID = item.ID, Title = item.Title });
}
}
dataGridView2.DataSource = listFinal;
现在datagrid正在显示数据。所以我的问题是....是否有任何捷径方式将结果转换为列表,因此我可以使用循环迭代将列表直接绑定到datagrid并创建新列表并在绑定之前填充它。寻求指导。感谢
答案 0 :(得分:3)
是的,只需在LINQ查询上调用.SelectMany()和.ToList()。
dataGridView2.DataSource = result.SelectMany(e => e).ToList();
或使用appropriate constructor创建您的列表:
dataGridView2.DataSource = new List(result.SelectMany(e => e));
答案 1 :(得分:1)
这应该这样做
var result = (from searchResult in list
let title = searchResult.Title.ToLower()
let key_string = to_search.FirstOrDefault(ts => title.Contains(ts))
orderby key_string == null ? -1 : title.Split(new[] { key_string }, StringSplitOptions.None).Length descending
group searchResult by key_string into Group
orderby Group.Count() descending
select Group).ToList();