(我的)SQL完全连接三个表

时间:2012-07-10 09:26:21

标签: mysql sql join

我有树表

ID    A
-----------
1     10

ID    B
-----------
1     20
2     30

ID    C
-----------
2     40
3     50

有人可以告诉我们如何制作视图或查询这样的打印件吗?

ID     A      B      C      R (A + B - C)
-----------------------------------
1     10     20      0     30
2      0     30     40    -10
3      0      0     50    -50

提前致谢。

3 个答案:

答案 0 :(得分:8)

据我所知,MySql中没有完整的外连接。因此,要执行您需要的操作,您应该在派生表中获取不同的ID并离开连接原始表:

select ids.id,
       ifnull(table1.A, 0) A,
       ifnull(table2.B, 0) B,
       ifnull(table3.C, 0) C,
       ifnull(table1.A, 0) + ifnull(table2.B, 0) - ifnull(table3.C, 0) R
  from 
  (
    select id
      from table1
    union
    select id
      from table2
    union
    select id
      from table3
  ) ids
  left join table1
    on ids.id = table1.id
  left join table2
    on ids.id = table2.id
  left join table3
    on ids.id = table3.id

答案 1 :(得分:0)

select coalesce(a.Id, b.Id, c.Id) ID, 
       case when a.A > 0 then a.A else 0 end, 
       case when b.B > 0 then b.B else 0 end,
       case when c.C > 0 then c.C else 0 end,
       ifnull(a.A, 0) + ifnull(b2.B, 0) - ifnull(c.C, 0) R
 from tableA a
 right outer join tableB b on a.id = b.id
 right outer join tableC c on b.id = c.id;

答案 2 :(得分:-1)

试试这个

  select t1.ID, t1.A,t2.B,t3.C,t1.A+t2.B-t3.C as R
  from tableA t1
  full outer join tableB t2 on t1.id =t2.id
  full outer join tableC t3 on t1.id =t3.id