我在SQL Server表中有一列包含以下行:
MyColumn:
1 Month
2 Week
10 Minutes
1 week
12 hours
1 days
2 month
2 day
5 minutes
1 hours
这是一个包含优先级字符串的文本列。
有没有办法让select这个列按照以下顺序返回:
10 Minutes
5 minutes
1 hours
10 Hours
1 day
2 days
1 week
2 weeks
1 month
2 months
等。
谢谢
答案 0 :(得分:1)
试试这个解决方案:
SELECT mycolumn
FROM tbl
ORDER BY
SUBSTRING(mycolumn, PATINDEX('%[^0-9]%', mycolumn)+1, 999),
CAST(LEFT(mycolumn, PATINDEX('%[^0-9]%', mycolumn)-1) AS INT)
答案 1 :(得分:0)
order by case when patindex('%Month', MyColumn) > 0
then 0
when patindex('%week', MyColumn) > 0
then 1
when patindex('%days', MyColumn) > 0
then 2
when patindex('%Minutes', MyColumn) > 0
then 3
end,
cast(substring(MyColumn, 1, CHARINDEX(' ', MyColumn)) as int)
答案 2 :(得分:0)
select T4.cnt +' '+T4.name from (
select substring(name, 1, CHARINDEX(' ', name)) cnt,substring(name,CHARINDEX(' ', name)+1,LEN(name)) name from test4) T4
left outer join (
select 1 as id,'Month' As name union all
select 2 as id,'Week' As name union all
select 3 as id,'Day' As name union all
select 4 as id,'Minutes' As name )T6
on t4.name=t6.name
order by t6.id,t4.cnt
你必须在左表中按照你想要的顺序给出所有不同的值(月,周等......)“union all”