Question

我认为我的逻辑是正确的但是while无限循环，输出为零。这是我的代码：

int currentMSD, currentNum = num;
if (currentNum >= 0 && currentNum < 100) {
    currentMSD = 10;
} else if (currentNum >= 100 && currentNum < 1000) {
    b1 = b * msd;
    b2 = num3 - b1;
    num3 = b2;
    switch(b) {
        case 1:
            cout << "one ";
            break;
        case 2:
            cout << "two ";
            cout << "five ";
            break;
        case 6:
            cout << "six ";
            break;
        case 9:
            cout << "nine ";
            break;
        case 0:
            cout << "zero ";
          break;
        }
    }
    cout << '\n';
}

Answer 1

您对250这样的东西有什么样的输出？ “二五零”？

这是一个简单的例子：

#include <iostream>

const char* nums[] = {"zero", "one", "two", "three", "four", 
                      "five", "six", "seven", "eight", "nine"};

void getMSD(unsigned int num)
{
    unsigned int remainder = num % 10;
    unsigned int result = num / 10;

    if(result > 0)
        getMSD(result);

    std::cout << nums[remainder] << " ";
}

int main()
{
    getMSD(125); //prints "one two five"

    return 0;
}

Answer 2

在getMSD功能中，您需要检查一位数：

int getMSD(int num) {
    int currentMSD, currentNum = num;

    if (currentNum < 10) {
        currentMSD = 1;
    } else if (currentNum >= 10 && currentNum < 100) {
        currentMSD = 10;
    } else if (currentNum >= 100 && currentNum < 1000) {
        currentMSD = 100;
    } else if (currentNum >= 1000 && currentNum < 10000) {
        currentMSD = 1000;
    }
    return currentMSD;
}

Answer 3

问题是你没有在“getMsd”函数中检查1到9的数字。但是，我不建议您使用此逻辑，因为它不可扩展。我的意思是你不能使用这个代码与6位数字

Answer 4

getMSD()功能有问题。用这个新的替换它

int getMSD(int num) {

int currentMSD = 1, currentNum = num;

if (currentNum >= 10 && currentNum < 100)
{
    currentMSD = 10;
}
else if (currentNum >= 100 && currentNum < 1000)
{
    currentMSD = 100;
}
else if (currentNum >= 1000 && currentNum < 10000)
{
    currentMSD = 1000;
}
return currentMSD;
}

Answer 5

你犯了一个逻辑错误。根据你的逻辑，你有250作为输入，

msd = 100 , then b = 250/100 = 2.5 = 2 which should output 'two'
b1 = msd * b = 100 * 2 = 200
b2 = num - b1 = 250 - 200 = 50
num = b2 = 50
repeat
msd = 10, then b = 50/10 = 5 which should then output 'five'
b1 = msd * b = 50
b2 = num - b1 = 50 - 50 = 0

如果输入为250但输入为205时，此逻辑工作正常。它将永远不会打印＆＃34;零＆＃34;因为当你减去num - b1 205-200时，你会得到5。

就您的计划而言，您滥用while条件，因为根据您的条件while (num3 > 0)，此条件永远不会打印最后一位数字。

希望你能指出我的意见。：）

Answer 6

做更多控制（美化）：

int getMSD(const int& num) {
   int currentMSD = 1;
   const int N = 3;  
   for(int j = 1, i = 1; j != N; ++j, i * 10) {
      if(num >= 10 * i && num < 100 * i) {
          currentMSD = 10 * i;
       }
   }          
   return currentMSD;
}

C ++将数字转换为单词

6 个答案: