Question

我有简单的jquery＆amp; php reg /登录脚本工作。基本上如果用户的名字和传递在数据库中，那么php回应为真，并且在我的javascript中我有

我想将用户名传回我的javascript并将其保存在变量中，我该怎么做？

我想在我的php中我可以这样：

json_encode(array("boolean" => "true", "username" => '$username'));

但我如何在jQuery中处理它呢？

$('#login').click(function(e){
      $.get("login.php",{username: $("#username").val(), password: $("#password").val()},function(data){
         if(data == "true"){

            alert("Logged in");
            $('#logindiv').slideUp();
            $('#gamediv').show(); 
            $('#registerdiv').hide();
            $('#gameheader').html(userloggedin);
         }else{
            alert("Not Logged in");
         }
      });
});

修改的login.php

if (isset($_GET['username'])&& isset($_GET['password'])) {
$username = $_GET['username'];
    $password = $_GET['password'];

$sql = mysql_query("SELECT * FROM members WHERE username='$username' AND password='$password'") or die(mysql_error()); 

       // Get member ID into a session variable
        $id = $row["id"];   
        session_register('id'); 
        $_SESSION['id'] = $id;
        // Get member username into a session variable
        $username = $row["username"];   
        session_register('username'); 
        $_SESSION['username'] = $username;
        $json = array("boolean" => "true", "username" => $username);

        echo(json_encode($json));
        //exit();

} else {
    echo "false";
}

main.html中 ...

$('#login').click(function(e){
      $.getJSON("login.php",{username: $("#username").val(), password: $("#password").val()},function(data){
         if(data.username!==undefined){
            alert(data.username);
            $('#logindiv').slideUp();
            $('#gamediv').show(); 
            $('#registerdiv').hide();
            $('#gameheader').html(data['username']);
         }else{

         }
      });
});

Answer 1

用户名将在$ .get：

返回的数据对象中

 $.get('login.php',params, function(data){
     if(data){
         alert(data.username); // that's the value from php
     }
 }

您可以对值进行大量检查：

    ... 
    if(data.username) // username isn't empty string, null, undefined
    if(data.username!==undefined) // if you got it at all

Answer 2

使用.getJSON（）：http://api.jquery.com/jQuery.getJSON/

然后使用

data.username

jQuery + php如何在数据对象中返回多个值？

2 个答案: