MySQL嵌套设置非子关系

Question

我有一组嵌套的组织，看起来像这样（节点是组织ID）：

1234是4499和3322的父母，但9905是“附属”，而不是真正的父母或子女，1234。

我相信leftedge，rightedge设置应该看起来像：

orgID | leftedge | rightedge
1234  |   1      |    6
4499  |   2      |    3
3322  |   4      |    5
9905  |   7      |    8

由于9905实际上不是1234的孩子，我不知道如何才能得到1234和9905之间的关系。我用来建立子关系的SQL是：

SELECT ost.orgid, ost.leftedge, ost.rightedge
  FROM tbl_organisationsettree ost 
  JOIN tbl_organisationsettree AS child_ost ON child_ost.leftedge BETWEEN ost.leftedge AND ost.rightedge 
   AND child_ost.supersetid = ost.supersetid 
 WHERE 1 
   AND ost.leftedge > 1 
   AND ost.rightedge <6 
GROUP BY child_ost.ID 
HAVING COUNT(child_ost.ID) = 1

Answer 1

查找任何非descedant节点或节点1234的祖先：

SELECT ost.*     --- whatever from `org` table
FROM tbl_organisationsettree AS ost 
   JOIN tbl_organisationsettree AS param
      ON  param.leftedge NOT BETWEEN ost.leftedge 
                                 AND ost.rightedge
      AND ost.leftedge NOT BETWEEN param.leftedge 
                               AND param.rightedge
WHERE param.orgID = 1234 

--- if you only root nodes:
---
--- AND NOT EXISTS 
---     ( SELECT *
---       FROM tbl_organisationsettree AS parent
---       WHERE ost.leftedge > parent.leftedge 
---         AND ost.leftedge < parent.rightedge
---     )
;