Question

我分别存储了第（10），第（4）和第（1993）年。如何将其与当前日期进行比较？如果日期匹配，则使用cron发送电子邮件至myemail@gmail.com。

这是代码：

<?php
include"connect_mysql.php";
$reminder_dates = mysql_query("SELECT*FROM registration_form");
while($row = mysql_fetch_array($reminder_dates)){
$main_dob_day = $row['main_dob_day'];
$main_dob_month = $row['main_dob_month'];   
$main_dob_year = $row['main_dob_year'];
}
?>

Answer 1

$main_date   = "{$main_dob_year}-{$main_dob_month}-{$main_dob_day}";
$todays_date = date("Y-m-d");
$today       = strtotime($todays_date);
$main_dt     = strtotime($main_date);

if($main_dt == $today)
{
  $valid = "send email";
  echo $valid;
}

它会起作用

Answer 2

也许是这样的：

$old_date = "2006-01-16"; // Create this from the 3 strings you have in the db
$old_date = strtotime($old_date); 

$todays_date = date("Y-m-d"); 
$todays_date = strtotime($todays_date); 


if ($old_date == $todays_date)
 print "equal";
else
 ....

编辑：在回复您的评论时，您可以使用日期功能获取当前日期和月份，如下所示：

$m = date("m");
$d = date("d");

Answer 3

您可以在SQL查询中进行正确的比较，然后循环会将电子邮件发送到查询返回的所有行：

<?php
    include"connect_mysql.php";
    $sql = "
        SELECT *
        FROM registration_form
        WHERE 
            main_dob_month = MONTH(CURDATE()) AND 
            main_dob_day = DAYOFMONTH(CURDATE())";

    $reminder_dates = mysql_query($sql);
    while($row = mysql_fetch_array($reminder_dates))
    {
        // send email(s)
    }
?>

PHP如何将数据库中的日期与当前日期进行比较

3 个答案: