我有两个实体,它们之间有关系。 这是我的第一个实体:
@Entity
@Table(name = "APPLICATION_DEVICE")
public class ApplicationDevice implements Serializable {
[...]
@Id
@ManyToOne
@JoinColumn(name = "udid", nullable=false)
public Device getDevice()
{
return device;
}
public void setDevice(Device device)
{
this.device = device;
}
@Id
public Long getApplicationId()
{
return applicationId;
}
public void setApplicationId(Long applicationId)
{
this.applicationId = applicationId;
}
[...]
请注意,它有一个包含两个字段的主键:applicationId和一个设备(它是另一个关系)。
我的另一个实体是:
@Entity
@Table(name = "SEGMENT_APPLICATION_DEVICES")
public class SegmentApplicationDevice
{
[...]
@Id
@GeneratedValue
public Long getId()
{
return id;
}
public void setId(Long id)
{
this.id = id;
}
@ManyToOne
public ApplicationDevice getApplicationDevice()
{
return applicationDevice;
}
public void setApplicationDevice(ApplicationDevice applicationDevice)
{
this.applicationDevice = applicationDevice;
}
[...]
这是hibernate在尝试映射这些实体时的例外情况:
Exception constructing service 'HibernateSessionSource': Error invoking service builder method org.apache.tapestry5.hibernate.HibernateCoreModule.buildHibernateSessionSource(Logger, List, RegistryShutdownHub) (at HibernateCoreModule.java:123) (for service 'HibernateSessionSource'): Foreign key (FK5B8CB9821C11FEAE:SEGMENT_APPLICATION_DEVICES [applicationDevice_applicationId])) must have same number of columns as the referenced primary key (APPLICATION_DEVICE [udid,applicationId])
我做错了什么?谢谢!
答案 0 :(得分:1)
ApplicationDevice具有由2列组成的复合ID。然而,ApplicationDevice的manytoone没有指定列(应该有2个),所以使用了一个带有“entityname_id”的列的默认值。
要缓解此问题,请在manytoone中指定两个列,这些列是ApplicationDevice的joincolumns。