Question

我目前正在使用GSON使用输入流/阅读器解析一个非常大的JSON文件。在我的Android设备上解析大约需要35秒，我从一些基准测试中了解到Jackson性能更好。但我无法找到如何使用jackson解析我的JSON文件。任何人都可以帮助我吗？

我的JSON看起来像这样：

[

    {
        "venue": { … }
    },
    {
        "venue": {
            "venue_seasons": [ … ],
            "address": "the address",
            "city": "the city",
            "name": "the name",
            "created_at": "2011-05-31T07:55:33Z",
            "latitude": 00.000000,
            "country": "the country",
            "internal_link_en": null,
            "internal_link_nl": null,
            "updated_at": "2011-09-15T14:46:09Z",
            "zipcode": "the zipcode",
            "foursquare_link": "foursquare url",
            "url": null,
            "id": 3,
            "tip": "some tip",
            "uid": "4ab5e205f964a520317620e3",
            "phone": "phonenr",
            "recommended": null,
            "website": "someurl",
            "venue_photos": [ … ],  //array containing objects with urls of images
            "description": null,
            "longitude": 00.000000,
            "thumbnail_location": null,
            "subcategories": [ … ],
            "opening_en": null,
            "opening_nl": null,
            "hidden": false,
            "twitter": "thetwitteraccount",
            "themes": [ … ]
        }
    }, //more venues
]

我的GSON代码看起来像这样，它有效：

AssetManager assetManager = getAssets();
InputStream inputStream = null;
try {
    inputStream = assetManager.open("filename.json");
} catch (IOException e) {
    Log.e("tag", e.getMessage());
}

Reader reader = new InputStreamReader(inputStream);

Gson gson = new Gson();
List<JsonResponse> venueList = gson.fromJson(reader, new TypeToken<List<JsonResponse>>() {}.getType());
JsonResponse naam = venueList.get(12);
String denaam = naam.venue.getName;
Log.i("nr12",denaam);
Log.i("timetracker","stop" ); 

// just some logging to test if the parser works 
for (JsonResponse venue : venueList) {
    String tijdel = String.valueOf(venue.venue.id);
    Log.i(venuetag,"name of venue"+ tijdel+ " is: " + venue.venue.getName);
}

...

class JsonResponse
{
    Venues venue;
}

class Venues
{
    public List<VenueSeasons> venue_seasons;

    public List<VenuePhotos> venue_photos;

    public List<SubCategories> subcategories;

    public List<Themes> themes;

    @SerializedName("address")
    public String getAdress;

    @SerializedName("city")
    public String getCity;

    @SerializedName("country")
    public String getCountry;

    @SerializedName("name")
    public String getName;

    @SerializedName("created_at")
    public Date getCreatedAt;

    @SerializedName("updated_at")
    public Date getUpdatedAt;

    @SerializedName("internal_link_nl")
    public String getInternalLinkNl;

    @SerializedName("internal_link_en")
    public String getInternalLinkEN;

    @SerializedName("latitude")
    public Double getLatitude;

    @SerializedName("longitude")
    public Double getLongitude;

    @SerializedName("foursquare_link")
    public String getFoursquareLink;

    @SerializedName("url")
    public String getURL;

    @SerializedName("phone")
    public String getPhone;

    @SerializedName("zipcode")
    public String getZipCode;

    public String tip;

    public String tip_en;

    public String uid;

    public int id;

    @SerializedName("website")
    public String getWebsite;

    @SerializedName("recommended")
    public Boolean getRecommended;

    @SerializedName("description")
    public String getDescription;

    @SerializedName("hidden")
    public Boolean getHidden;

    @SerializedName("opening_en")
    public String getOpeningEN;

    @SerializedName("opening_nl")
    public String getOpeningNL;

    @SerializedName("twitter")
    public String getTwitter;

    @SerializedName("thumbnail_location")
    public String getThumbnailLocation;
}


public class VenuePhotos 
{
    @SerializedName("large")
    public String getLargePhotoURL;

    @SerializedName("medium")
    public String getMediumPhotoURL;

    @SerializedName("small")
    public String getSmallPhotoURL; 

    @SerializedName("original")
    public String getOriginalPhotoURL;

    public String uid;

    public int id;

    public int venue_id;

    public boolean selected;

    @SerializedName("created_at")
    public Date getCreatedAt;

    @SerializedName("updated_at")
    public Date getUpdatedAt;
}

现在这个有效。我做了一些关于数据的东西，解析后它的工作效果都很棒，但是我觉得应用程序启动时间太长了。

我的杰克逊代码（失败的代码）是：

AssetManager assetManager = getAssets();
InputStream inputStream = null;
try {
    inputStream = assetManager.open("originalDelftJson.json");
} catch (IOException e) {
    Log.e("tag", e.getMessage());
}
Reader reader = new InputStreamReader(inputStream);

ObjectMapper objectMapper = new ObjectMapper();
JsonFactory jsonFactory = new JsonFactory();
JJsonResponse response = null;
try {
    JsonParser jp = jsonFactory.createJsonParser(reader);
    response = objectMapper.readValue(jp, JJsonResponse.class);
    String test = String.valueOf(response.venue.size());

使用课程：

public class JJsonResponse
{
     public List<JVenue> venue;
}

class Venues
{
    public List<VenueSeasons> venue_seasons;

    public List<VenuePhotos> venue_photos;

    public List<SubCategories> subcategories;

    public List<Themes> themes;

    @SerializedName("address")
    public String getAdress;

    @SerializedName("city")
    public String getCity;

    @SerializedName("country")
    public String getCountry;

    @SerializedName("name")
    public String getName;

    @SerializedName("created_at")
    public Date getCreatedAt;

    @SerializedName("updated_at")
    public Date getUpdatedAt;

    @SerializedName("internal_link_nl")
    public String getInternalLinkNl;

    @SerializedName("internal_link_en")
    public String getInternalLinkEN;

    @SerializedName("latitude")
    public Double getLatitude;

    @SerializedName("longitude")
    public Double getLongitude;

    @SerializedName("foursquare_link")
    public String getFoursquareLink;

    @SerializedName("url")
    public String getURL;

    @SerializedName("phone")
    public String getPhone;

    @SerializedName("zipcode")
    public String getZipCode;

    public String tip;

    public String tip_en;

    public String uid;

    public int id;

    @SerializedName("website")
    public String getWebsite;

    @SerializedName("recommended")
    public Boolean getRecommended;

    @SerializedName("description")
    public String getDescription;

    @SerializedName("hidden")
    public Boolean getHidden;

    @SerializedName("opening_en")
    public String getOpeningEN;

    @SerializedName("opening_nl")
    public String getOpeningNL;

    @SerializedName("twitter")
    public String getTwitter;

    @SerializedName("thumbnail_location")
    public String getThumbnailLocation;
}

public class JVenue
{
    public String name;
    public int id;
    public String city;
    public String address;
    public String country;
    public String internal_link_nl;
    public String internal_link_en;
    public String zipcode;
    public String foursquare_link;
    public String tip_en;
    public String url;
    public Date created_at;
    public Date updated_at;
    public float latitude;
    public float longitude;
    public String tip;
    public String uid;
    public String phone;
    public String recommended;
    public String website;
    public String description;
    public String thumbnail_location;
    public boolean hidden;
    public String twitter;
    public String opening_en;
    public String opening_nl;
}

我认为我非常接近，但我做错了，因为我收到了错误：org.codehaus.jackson.map.JsonMappingException: Can not deserialize instance of com.jacksonrecipes.testapp.model.JJsonResponse out of START_ARRAY token

我真的不了解杰克逊的工作方式以及如何实施杰克逊。有谁知道如何在我的Android代码中更改我的Jackson实现，以便它可以工作，我可以访问数据？

编辑：获得我的解决方案

借助MH的答案。我能找到它。我现在用：

List<JJsonResponse> venueCounter = objectMapper.readValue(inputStream, new TypeReference<List<JJsonResponse>>() { });

Answer 1

以下是使用Jackson的一个工作示例，其中原始问题中的JSON（已更正为有效且与Java数据结构相匹配）与来自原始Gson示例的Java数据结构（已更正为使用Jackson的{{1而不是Gson的@JsonProperty）。

@SerializedName

Answer 2

要记住的一件非常重要的事情是，您总是希望重用ObjectMapper个实例 - 每个请求创建一个实例会减少很多事情，可能会减少一个数量级。通常只需创建一个静态实例（在创建后立即配置），或者通过像Guice这样的DI框架注入一个静态实例。

杰克逊的其他表现最佳做法可以在以下网址找到：http://wiki.fasterxml.com/JacksonBestPracticesPerformance

Answer 3

看起来你的Json内容只是一个对象列表。这意味着，从我的头脑中，你的代码需要看起来像这样：

List<JVenue> venues = mapper.readValue(inputStream, new TypeReference<List<JVenue>>() { });

无需将InputStream包裹在Reader中，也无需创建自己的JsonFactory和JsonParser个实例。

从Gson更改为Jackson以进行JSON解析

3 个答案: