Question

默认情况下，Gson使用字段作为序列化的基础。有没有办法让它使用访问器？

Answer 1

Gson say的开发人员，他们从未因添加此功能的请求而感到动摇，他们担心会滥用api来增加对此的支持。

添加此功能的一种方法是使用TypeAdapter（我为粗糙的代码道歉，但这证明了原理）：

import java.io.IOException;
import java.lang.annotation.Retention;
import java.lang.annotation.RetentionPolicy;
import java.lang.reflect.InvocationTargetException;
import java.lang.reflect.Method;

import com.google.common.base.CaseFormat;
import com.google.gson.Gson;
import com.google.gson.TypeAdapter;
import com.google.gson.reflect.TypeToken;
import com.google.gson.stream.JsonReader;
import com.google.gson.stream.JsonWriter;

public class AccessorBasedTypeAdaptor<T> extends TypeAdapter<T> {

  private Gson gson;

  public AccessorBasedTypeAdaptor(Gson gson) {
    this.gson = gson;
  }

  @SuppressWarnings("unchecked")
  @Override
  public void write(JsonWriter out, T value) throws IOException {
    out.beginObject();
    for (Method method : value.getClass().getMethods()) {
      boolean nonBooleanAccessor = method.getName().startsWith("get");
      boolean booleanAccessor = method.getName().startsWith("is");
      if ((nonBooleanAccessor || booleanAccessor) && !method.getName().equals("getClass") && method.getParameterTypes().length == 0) {
        try {
          String name = method.getName().substring(nonBooleanAccessor ? 3 : 2);
          name = CaseFormat.UPPER_CAMEL.to(CaseFormat.LOWER_CAMEL, name);
          Object returnValue = method.invoke(value);
          if(returnValue != null) {
            TypeToken<?> token = TypeToken.get(returnValue.getClass());
            TypeAdapter adapter = gson.getAdapter(token);
            out.name(name);
            adapter.write(out, returnValue);
          }
        } catch (Exception e) {
          throw new ConfigurationException("problem writing json: ", e);
        }
      }
    }
    out.endObject();
  }

  @Override
  public T read(JsonReader in) throws IOException {
    throw new UnsupportedOperationException("Only supports writes.");
  }
}

您可以将此注册为给定类型的普通类型适配器或通过TypeAdapterfactory注册 - 可能检查是否存在运行时注释：

public class TypeFactory implements TypeAdapterFactory {

  @SuppressWarnings("unchecked")
  public <T> TypeAdapter<T> create(final Gson gson, final TypeToken<T> type) {
    Class<? super T> t = type.getRawType();
    if(t.isAnnotationPresent(UseAccessor.class)) {
     return (TypeAdapter<T>) new AccessorBasedTypeAdaptor(gson);
    }
    return null;
  }

创建gson实例时可以正常指定：

new GsonBuilder().registerTypeAdapterFactory(new TypeFactory()).create();

Answer 2

注意：我是EclipseLink JAXB (MOXy)主管，是JAXB (JSR-222)专家组的成员。

如果你不能让Gson做你想做的事，下面是你如何使用MOXy的原生JSON绑定来实现这一目标。像任何JAXB实现一样MOXy默认使用属性（公共）访问。您可以使用@XmlAccessorType(XmlAccessType.FIELD)配置字段访问权限。以下是一个例子：

<强>客户

package forum11385214;

public class Customer {

    private String foo;
    private Address bar;

    public String getName() {
        return foo;
    }

    public void setName(String name) {
        this.foo = name;
    }

    public Address getAddress() {
        return bar;
    }

    public void setAddress(Address address) {
        this.bar = address;
    }

}

<强>地址

package forum11385214;

public class Address {

    private String foo;

    public String getStreet() {
        return foo;
    }

    public void setStreet(String street) {
        this.foo = street;
    }

}

<强> jaxb.properties

要将MOXy配置为JAXB提供程序，您需要在与域模型相同的程序包中添加名为jaxb.properties的文件，并带有以下条目（请参阅：http://blog.bdoughan.com/2011/05/specifying-eclipselink-moxy-as-your.html）。

javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory

<强>演示

package forum11385214;

import java.util.*;
import javax.xml.bind.*;
import javax.xml.transform.stream.StreamSource;
import org.eclipse.persistence.jaxb.JAXBContextProperties;

public class Demo {

    public static void main(String[] args) throws Exception {
        Map<String, Object> properties = new HashMap<String, Object>(2);
        properties.put(JAXBContextProperties.MEDIA_TYPE, "application/json");
        properties.put(JAXBContextProperties.JSON_INCLUDE_ROOT, false);
        JAXBContext jc = JAXBContext.newInstance(new Class[] {Customer.class}, properties);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        StreamSource json = new StreamSource("src/forum11385214/input.json");
        Customer customer = (Customer) unmarshaller.unmarshal(json, Customer.class).getValue();

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(customer, System.out);
    }

}

<强> input.json /输出

{
    "name" : "Jane Doe",
    "address" : {
        "street" : "1 Any Street"
    }
}

了解更多信息

如何让Gson使用访问者而不是字段？

2 个答案: