Question

好的，所以我有两个列表，一个单词，如下：

["happy", "sad", "angry", "jumpy"]

等

然后是一个短语列表，如下：

["I'm so happy with myself lately!", "Johnny, im so sad, so very sad, call me", "i feel like crap. SO ANGRY!!!!"]

我想使用第一个单词列表来查找短语列表中单词的发生率。我不在乎我是否拉出实际的单词，用空格或它们出现的次数分开。

从我的研究看来，似乎re模块和过滤器是可行的方法吗？

另外，如果我对我所需要的解释不清楚，请告诉我。

Answer 1

>>> phrases = ["I'm so happy with myself lately!", "Johnny, im so sad, so very sad, call me", "i feel like crap. SO ANGRY!!!!"]
>>> words = ["happy", "sad", "angry", "jumpy"]
>>> 
>>> for phrase in phrases:
...     print phrase
...     print {word: phrase.count(word) for word in words}
... 
I'm so happy with myself lately!
{'jumpy': 0, 'angry': 0, 'sad': 0, 'happy': 1}
Johnny, im so sad, so very sad, call me
{'jumpy': 0, 'angry': 0, 'sad': 2, 'happy': 0}
i feel like crap. SO ANGRY!!!!
{'jumpy': 0, 'angry': 0, 'sad': 0, 'happy': 0}

Answer 2

非常简单，直接的解决方案：

>>> phrases = ["I'm so happy with myself lately!", "Johnny, im so sad, so very sad, call me", "i feel like crap. SO ANGRY!!!!"]
>>> words = ["happy", "sad", "angry", "jumpy"]
>>> for phrase in phrases:
        for word in words:
            if word in phrase:
                print('"{0}" is in the phrase "{1}".'.format(word, phrase))

"happy" is in the phrase "I'm so happy with myself lately!".
"sad" is in the phrase "Johnny, im so sad, so very sad, call me".

Answer 3

>>> phrases = ["I'm so happy with myself lately!", "Johnny, im so sad, so very sad, call me", "i feel like crap. SO ANGRY!!!!"]
>>> words = ["happy", "sad", "angry", "jumpy"]
>>> words_in_phrases = [re.findall(r"\b[\w']+\b", phrase.lower()) for phrase in phrases]
>>> words_in_phrases
[["i'm", 'so', 'happy', 'with', 'myself', 'lately'], ['johnny', 'im', 'so', 'sad', 'so', 'very', 'sad', 'call', 'me'], ['i', 'feel', 'like', 'crap', 'so', 'angry']]
>>> word_counts = [{word: phrase.count(word) for word in words} for phrase in words_in_phrases]
>>> word_counts
[{'jumpy': 0, 'angry': 0, 'sad': 0, 'happy': 1}, {'jumpy': 0, 'angry': 0, 'sad': 2, 'happy': 0}, {'jumpy': 0, 'angry': 1, 'sad': 0, 'happy': 0}]
>>>

对于行word_counts = [{word: phrase.count(word) for word in words} for...，您需要Python 2.7+。如果出于某种原因，您正在使用＆lt; Python 2.7，用以下内容替换该行：

>>> word_counts = [dict((word, phrase.count(word)) for word in words) for phrase in words_in_phrases]

两个列表，一个单词，一个短语

3 个答案: