Question

这是我想要做的：我有一个以下命令：

result=`awk /^#.*/{print;getline;print} file1.txt
echo "$result"

输出是：

#first comment
first line
#second comment
second line
#third comment
third line.

如果我必须将$ result放入while循环并将两行作为一个字符串变量捕获并打印出来，我该怎么办呢？

示例：

echo "$result" | while read m
do
echo "Value of m is: $m"
done

输出是：

Value of m is:#first comment
Value of m is:first line
Value of m is:#second comment
Value of m is:second line
Value of m is:#third comment
Value of m is:third line.

但是预期的输出是：

Value of m is:
#first comment
first line
Value of m is:
#second comment
second line
Value of m is:
#third comment
third line.

Answer 1

while read -r first; read -r second
do
    printf '%s\n' 'Value of m is:' "$first" "$second"
done

或者如果您需要变量中的行：

while read -r first; read -r second
do
    m="$first"$'\n'"$second"
    echo 'Value of m is:'
    echo "$m"
done

Answer 2

使用awk的一种方法。在每个奇数行中读取下一个并在换行符之间连接它们。

awk '
    FNR % 2 != 0 { 
        getline line; 
        result = $0 "\n" line; 
        print "Value:\n" result; 
    }
' infile

假设infile的内容为：

#first comment
first line
#second comment
second line
#third comment
third line.

运行上一个awk命令输出将是：

值：

Value:
#first comment
first line
Value:
#second comment
second line
Value:
#third comment
third line.

同时读取两行作为一个字符串变量

2 个答案: