Question

我正在尝试使用嵌套循环搜索用户输入的文本数组和另一个用户输入的搜索词数组，然后输出搜索词与它们在文本中出现的次数以及总文本的百分比。我认为我在正确的轨道上，我的问题是，每次if语句为真时，计数器都不会重置。我对编程很陌生 - 所以我可能完全错了。以下是整个计划。如果有人可以看看并帮我弄清楚我的问题是什么，我会永远感激。

public class termFrequency {
    public static void main(String[] args) {

        String searchTextPeriod, searchTextComma, searchTextApostrophe, searchTextColon, searchTextExclamation, 
        searchTextQuestion, searchText, searchTerm;
        int counter=0, total, searchIndex=0, termIndex=0;
        double percentage=0.0;
        String [] searchArray, termArray;


        searchText = JOptionPane.showInputDialog("Enter a sentence that is at least 20 words long");

        //removes some common punctuation from the searchable text
        searchTextPeriod = searchText.replace(".", "");
        searchTextComma = searchTextPeriod.replace(",", "");
        searchTextApostrophe = searchTextComma.replace("'", " ");
        searchTextColon = searchTextApostrophe.replace(":", " ");
        searchTextExclamation = searchTextColon.replace("!", "");
        searchTextQuestion = searchTextExclamation.replace("?", "");

        searchArray = searchTextQuestion.split(" "); //splits the sentence and and puts it into an array

        total=searchArray.length;
        System.out.println("There are " +total +" words in your sentence");

        searchTerm = JOptionPane.showInputDialog("Enter your search terms here seperated by a space");
        termArray = searchTerm.split(" ");
        DecimalFormat two = new DecimalFormat("#0.00");

        boolean found = false;
        for (termIndex=0; termIndex<termArray.length; termIndex++) 
        {
            for (searchIndex=0; searchIndex<searchArray.length; searchIndex++) 

                if (termArray[termIndex].equalsIgnoreCase(searchArray[searchIndex]))
                {
                    counter++; 
                    found = true;

                    percentage= ((double) counter/(double)total) * 100;
                }
                if (found) 
                    System.out.println("Search word " + "\'" + termArray[termIndex] + "\' is found " +counter +" times. That is "+ two.format(percentage)+"% of the statement." );
                else  
                    System.out.println("Search word " + "\'" + termArray[termIndex] + "\' is not found in the statement.");

            }
        }
    }
}

Answer 1

在第一个循环内移动found = false。这样，每次迭代都会重置为false。现在，如果它被改为真，它将在剩下的过程中保持正确。

Answer 2

你必须将“找到”的if / else从内部循环移动到第一个循环的末尾。您还需要在第一个循环中重置布尔值和计数器，就像您开始使用初始值分析termArray中的每个新单词一样。

   for (termIndex=0; termIndex<termArray.length; termIndex++) 
    {
        counter=0; //Reset the counter for each word in termArray
        found=false; //Reset the "found" flag for each word in termArray
        for (searchIndex=0; searchIndex<searchArray.length; searchIndex++) 

            if (termArray[termIndex].equalsIgnoreCase(searchArray[searchIndex]))
            {
                counter++;
                percentage= ((double) counter/(double)total) * 100;

                found=true
                System.out.println("Search word " + "\'" + termArray[termIndex] + "\' is found " +counter +" times. That is "+ two.format(percentage)+"% of the statement." );
            }
        }
        if (found) 
                System.out.println("Search word " + "\'" + termArray[termIndex] + "\' is found " +counter +" times. That is "+ two.format(percentage)+"% of the statement." );
        else  
                System.out.println("Search word " + "\'" + termArray[termIndex] + "\' is not found in the statement.");

    }

顺便说一下，你真的不需要“找到”var，现在如果counter == 0你知道在searchArray中找不到这个词。

使用数组搜索字符串数组

2 个答案: