我有一个表单,我希望能够根据需要多次复制一组字段。我还想让字段id
,name
和这些新字段组的标签for
属性增加1.我到目前为止已经尝试过使用jQuery,并且得到了它至少复制字段组,但删除不起作用。而且我不确定如何为这3个属性中的每一个做+1。我感谢任何帮助。
这是一个jsfiddle,它 http://jsfiddle.net/Unfxn/
HTML
<form method="post" action="#" class="inlineForm" enctype="multipart/form-data">
<div class="repeatingSection">
<a href="#" class="buttonGray buttonRight deleteFight">Delete</a>
<input type="hidden" name="fighter_a_id_1" id="fighter_a_id_1" value="" />
<input type="hidden" name="fighter_b_id_1" id="fighter_b_id_1" value="" />
<input type="hidden" name="winner_id_1" id="winner_id_1" value="" />
<div class="formRow">
<label for="fighter_a_1">Fighters</label>
<input type="text" name="fighter_a_1" id="fighter_a_1" value="" /> <span class="formTextExtraCenter">vs</span> <input type="text" name="fighter_b_1" id="fighter_b_1" value="" />
</div>
<div class="formRow">
<label for="fighter_a_pay_1">Fighter Pay $</label>
<input type="text" name="fighter_a_pay_1" id="fighter_a_pay_1" value="" /> <span class="formTextExtraCenter">vs</span> <input type="text" name="fighter_b_pay_1" id="fighter_b_pay_1" value="" />
</div>
<div class="formRow">
<label for="winner_1">Winner</label>
<input type="text" name="winner_1" id="winner_1" value="" />
</div>
<div class="formRow">
<label for="method_1">Method</label>
<input type="text" name="method_1" id="method_1" value="" />
</div>
<div class="formRow">
<label for="method_type_1">Method Type</label>
<input type="text" name="method_type_1" id="method_type_1" value="" />
</div>
<div class="formRow">
<label for="round_1">Round</label>
<input type="text" name="round_1" id="round_1" class="fieldSmall" value="" />
</div>
<div class="formRow">
<label for="time_1">Time</label>
<input type="text" name="time_1" id="time_1" class="fieldSmall" value="" />
</div>
<div class="formRow">
<label for="fight_number_1">Fight #</label>
<input type="text" name="fight_number_1" id="fight_number_1" class="fieldSmall" value="" />
</div>
</div>
<div class="formRowRepeatingSection">
<a href="#" class="buttonGray buttonRight addFight">Add Fight</a>
</div>
<div class="formRow">
<input type="submit" class="submitButton" value="Save Fights" />
</div>
</form>
JS
// Add a new repeating section
$('.addFight').click(function(){
var lastRepeatingGroup = $('.repeatingSection').last();
lastRepeatingGroup.clone().insertAfter(lastRepeatingGroup);
return false;
});
// Delete a repeating section
$('.deleteFight').click(function(){
$(this).parent('div').remove();
return false;
});
答案 0 :(得分:6)
这应该根据所有三个元素自动重命名:
// Add a new repeating section
$('.addFight').click(function(){
var currentCount = $('.repeatingSection').length;
var newCount = currentCount+1;
var lastRepeatingGroup = $('.repeatingSection').last();
var newSection = lastRepeatingGroup.clone();
newSection.insertAfter(lastRepeatingGroup);
newSection.find("input").each(function (index, input) {
input.id = input.id.replace("_" + currentCount, "_" + newCount);
input.name = input.name.replace("_" + currentCount, "_" + newCount);
});
newSection.find("label").each(function (index, label) {
var l = $(label);
l.attr('for', l.attr('for').replace("_" + currentCount, "_" + newCount));
});
return false;
});
// Delete a repeating section
$('.deleteFight').live('click',function(){
$(this).parent('div').remove();
return false;
});
我更改了删除处理程序,改为使用.live(),以便处理程序也可以附加到该按钮的新创建副本。现在,如果您正在使用jquery&gt; 1.7你应该使用.on()
on()版本将是:
// Delete a repeating section
$(document).on('click','.deleteFight',function(){
$(this).parent('div').remove();
return false;
});
答案 1 :(得分:2)
这是我的版本。
它在很大程度上依赖于重复区域的索引。所以不要在它上面添加任何兄弟姐妹。如果确实需要,请将所有重复区域包装在另一个div中。
该死!太晚了:)无论如何......这是代码。
// Add a new repeating section
var attrs = ['for', 'id', 'name'];
function resetAttributeNames(section) {
var tags = section.find('input, label'), idx = section.index();
tags.each(function() {
var $this = $(this);
$.each(attrs, function(i, attr) {
var attr_val = $this.attr(attr);
if (attr_val) {
$this.attr(attr, attr_val.replace(/_\d+$/, '_'+(idx + 1)))
}
})
})
}
$('.addFight').click(function(e){
e.preventDefault();
var lastRepeatingGroup = $('.repeatingSection').last();
var cloned = lastRepeatingGroup.clone(true)
cloned.insertAfter(lastRepeatingGroup);
resetAttributeNames(cloned)
});
// Delete a repeating section
$('.deleteFight').click(function(e){
e.preventDefault();
var current_fight = $(this).parent('div');
var other_fights = current_fight.siblings('.repeatingSection');
if (other_fights.length === 0) {
alert("You should atleast have one fight");
return;
}
current_fight.slideUp('slow', function() {
current_fight.remove();
// reset fight indexes
other_fights.each(function() {
resetAttributeNames($(this));
})
})
});
答案 2 :(得分:1)
克隆对象后使用此功能
摆弄:) http://jsfiddle.net/fedmich/MZjKR/1/
我会为你留下一些TODO,将3更改为当前的id
<script type="text/javascript">
$.fn.id_changer = function(new_id) {
return this.each(function(){
$(this).find('input').each(function(){
var ob = $(this);
ob.attr('id', this.id.replace(/_\d$/, '_' + new_id));
ob.attr('name', this.name.replace(/_\d$/, '_' + new_id));
});
});
};
答案 3 :(得分:0)
如果您使用 name=method[]
等作为您的字段,您将在 POST 变量中获得数组,因此您不需要显式索引。