如何从函数返回变量？

Question

我试图从函数返回一个变量并将其打印出来。它现在显示意外的T_STRING ....有人可以帮忙吗？

function reg_word($i){
        $reg_word = "/[^A-Za-z0-9 ]/";
        $i = preg_replace($reg_word, '', $i);
    }

$suggestion = function reg_word($_POST['suggestions']);

    print_r($suggestion);

Answer 1

function reg_word($i){
    $reg_word = "/[^A-Za-z0-9 ]/";
    return preg_replace($reg_word, '', $i);
}

$suggestion = reg_word($_POST['suggestions']);

print_r($suggestion);

function之前您有reg_word($_POST['suggestions']);个关键字 - 您不需要它。 您需要使用return关键字从函数中返回一些内容。

Answer 2

您有一个function个关键字错误，请尝试：

function reg_word($i){
        $reg_word = "/[^A-Za-z0-9 ]/";
        $i = preg_replace($reg_word, '', $i);
    }

$suggestion = reg_word($_POST['suggestions']);

    print_r($suggestion);

Answer 3

错误的function关键字，您不会在函数中返回任何值。

function reg_word($i){
        $reg_word = "/[^A-Za-z0-9 ]/";
        return preg_replace($reg_word, '', $i); // return added
    }

$suggestion = reg_word($_POST['suggestions']); // here function was

    print_r($suggestion);