我在R中有我的数据表。我想合并具有相同customerID
的行,然后连接其他合并列的元素。
我想离开这个:
title author customerID
1 title1 author1 1
2 title2 author2 2
3 title3 author3 1
到此:
title author Group.1
1 title1, title3 author1, author3 1
2 title2 author2 2
答案 0 :(得分:13)
aggregate
功能可以帮助您找到解决方案:
dat = data.frame(title = c("title1", "title2", "title3"),
author = c("author1", "author2", "author3"),
customerID = c(1, 2, 1))
aggregate(dat[-3], by=list(dat$customerID), c)
# Group.1 title author
# 1 1 1, 3 1, 3
# 2 2 2 2
或者,只需确保在创建数据框时添加stringsAsFactors = FALSE
,然后就可以了。如果您的数据已经考虑因素,您可以使用类似dat[c(1, 2)] = apply(dat[-3], 2, as.character)
的内容将其转换为字符,然后:
aggregate(dat[-3], by=list(dat$customerID), c)
# Group.1 title author
# 1 1 title1, title3 author1, author3
# 2 2 title2 author2
答案 1 :(得分:2)
也许不是最好的解决方案,但很容易理解:
df <- data.frame(author=LETTERS[1:5], title=LETTERS[1:5], id=c(1, 2, 1, 2, 3), stringsAsFactors=FALSE)
uniqueIds <- unique(df$id)
mergedDf <- df[1:length(uniqueIds),]
for (i in seq(along=uniqueIds)) {
mergedDf[i, "id"] <- uniqueIds[i]
mergedDf[i, "author"] <- paste(df[df$id == uniqueIds[i], "author"], collapse=",")
mergedDf[i, "title"] <- paste(df[df$id == uniqueIds[i], "title"], collapse=",")
}
mergedDf
# author title id
#1 A,C A,C 1
#2 B,D B,D 2
#3 E E 3