Question

我有这种格式的字符串： "a = 23, b = 432, f = 321, gfs = 413, d = 42, k = 4242, t = 4314, (...etc...)" - 约30个元素

我需要有可能在相应的字符串中搜索4个元素，例如：a，b，d，k。

例如，口头查询：give me all string where a = 3, b, = 2, d = 31, k = 1

我应该使用哪种收藏品？想要创建一类课程吗？有什么想法吗？

Answer 1

如果你知道你的值是唯一的，我会构建一个哈希表，其中等号的左边是你的键，右边是你的值。这将帮助您避免任何可能改变的字符串形成，例如额外的空格等。

这是一些代码示例

static void Main(string[] args)
{
    string str = "a = 23, b = 432, f = 321, gfs = 413, d = 42, k = 4242, t = 4314";
    Dictionary<string,string> dictionary = ConstructDictionary(str);
    // Now you can find what you want in your dictionary
}

private static Dictionary<string,string> ConstructDictionary(string str)
{
    string[] pairs = str.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries); // this will give you all the pairs X = Y
    Dictionary<string, string> dictionary = new Dictionary<string, string>();
    foreach (string pair in pairs)
    {
        string[] keyValue = pair.Split(new char[] { '=' }, StringSplitOptions.RemoveEmptyEntries); // this will create an array of size 2 where 
        array[0] = key and array[1] = value;
        string key = keyValue[0].Trim();
        string value = keyValue[1].Trim();
        if (!dictionary.ContainsKey(key))
        {
            dictionary.Add(key, value);
        }
    }
    return dictionary;
}

Answer 2

以下是使用辅助功能的一种方法：

private static bool HasAll(string s, string[] keys, int[] vals) {
    if (keys.Length != vals.Length) throw new ArgumentException("vals");
    var tt = s.Split(new[] {' ', ',', '='});
    for(var i = 0 ; i != keys.Length ; i++) {
        var pos = Array.IndexOf(tt, keys[i]));
        if (pos < 0 || pos == vals.Length-1 || !tt[i+1].Equals(vals[i].ToString())) {
            return false;
        }
    }
    return true;
}

现在您可以使用LINQ来获取这样的项目：

var keys = new[] {"a", "b", "d", "k"};
var vals = new[] {3, 2, 31, 1};
var res = data.Where(str => HasAll(str, keys, vals)).ToList();

Answer 3

如果我正确理解了问题，那就应该这样做

1）创建一个字典，其中键是完整字符串，值是字符串的分割部分

2）检查标准与碎片的交叉点。交叉点大小与条件大小相同，我们有匹配。

[TestMethod]
public void FindValuesInStrings() {

  var strings = new[] {
     "a = 23, b = 432, f = 321, gfs = 11, d = 42, k = 4242, t = 4314",   //A
     "a = 12, b = 123, f = 456, gfs = 11, d = 42, k = 4242, t = 4314",   //B
     "a = 11, b = 456, f = 789, gfs = 413, d = 42, k = 4242, t = 4314",  //C
     "a = 23, b = 789, f = 12,  gfs = 13, d = 42, k = 4242, t = 4314",   //D
  };


   var dict = new Dictionary<string, IEnumerable<string>>();
   foreach (var str in strings) {
      dict.Add(str, str.Split(',').Select(s => s.Trim()));
   }


   // finds the two entries where a = 23 (A & D)
   var criteria = new[] { "a = 23" };
   var found = dict.Where(entry => 
       entry.Value.Intersect(criteria).Count() == criteria.Count()).Select(entry => entry.Key);

   Assert.AreEqual(2, found.Count());

   // finds the single entry where a = 23 and gfs = 11 (A)
   criteria = new[] { "a = 23", "gfs = 11" };
   found = dict.Where(entry => 
        entry.Value.Intersect(criteria).Count() == criteria.Count()).Select(entry => entry.Key);

   Assert.AreEqual(1, found.Count());

}

Answer 4

这样的查询会起作用，但我建议将值放在与字符串不同的数据结构中。可能是带有元素名称的结构，以便您可以查找多个值。

string s1 = "a = 32, b = 432, f = 321, gfs = 43, d = 42, k = 4, t = 44";
string s2 = "a = 23, b = 432, f = 321, gfs = 413, d = 42, k = 4242, t = 4314";
string s3 = "a = 23, b = 21, f = 321, gfs = 413, d = 42, k = 4242, t = 4314";
var array = new string[] { s1, s2, s3 };

var result = array.Where(s => s.Contains("f = 321") && s.Contains("b = 432"));

在字符串集合中搜索

4 个答案: