Question

我正在尝试解析并从Web服务获取值。问题是Web服务具有相同的元素名称标记，这些标记创建了要解析的问题，因为我想获取它们的值，但它们具有相同的名称所以我很难将它们称为localname。

 <countryBean>
        <id>236</id>
        <name>United State</name>
    </countryBean>
    <secutiryQuestion1>
        <id>2</id>
        <question>What was your dream job as a child?</question>
    </secutiryQuestion1>
    <secutiryQuestion2>
        <id>4</id>
        <question>What is the name, breed, and color of your pet?</question>
    </secutiryQuestion2>
    <stateBean>
        <country>236</country>
        <id>5</id>
        <name>California</name>
    </stateBean>
    <statusBean>
        <id>1</id>
        <name>Active</name>
    </statusBean>

我希望得到ID标签和其他相邻标签的值，如名称，不同变量中的问题。这里有5个Id标签。

我的班级代码就像

public class XmlParser extends DefaultHandler {

        public RestfullResponse tempResponse = null;
        String currentValue = null;
        int ServiceType =0;

        @Override
        public void startElement(String uri, String localName, String qName,
                Attributes attributes) throws SAXException {
            if(localName.equalsIgnoreCase("countryBean")){
                tempResponse=new RestfullResponse();

                }           

        }


        /* (non-Javadoc)
         * @see org.xml.sax.helpers.DefaultHandler#endElement(java.lang.String, java.lang.String, java.lang.String)
         */
        @Override
        public void endElement(String uri, String localName, String qName)
                throws SAXException {
            if(ServiceType == 1)
            {
                if(localName.equalsIgnoreCase("id")){
                    tempResponse.setCountryId(currentValue);
                }
                if(localName.equalsIgnoreCase("name")){
                    tempResponse.setCountryName(currentValue);
                }

                if(localName.equalsIgnoreCase("id")){
                    tempResponse.setStateId(currentValue);
                }
                if(localName.equalsIgnoreCase("question")){
                    tempResponse.setstateBean(currentValue);
                }

                if(localName.equalsIgnoreCase("Id")){
                    tempResponse.setStatusId(currentValue);
                }
                if(localName.equalsIgnoreCase("requestSuccess")){
                    tempResponse.setStatus(currentValue);
                }
            }
        }

        @Override
        public void characters(char[] ch, int start, int length)
                throws SAXException {
            currentValue = new String(ch, start, length);
        }

        public RestfullResponse getResponse(){
            return tempResponse;
        }
}

请帮助将它们存储在

中

String CountryName= "";
String CountryId = "";
String Statename = "";
String StateId ="";
String Status = "";
String StatusId = "";
String Username ="";
String SecurityQuestion = "";
String SecurityQuestionId = "";

Answer 1

添加布尔变量isCountryBean;

boolean isCountryBean = false , isSecurityQuestion1 = false;

在startElement（....）中写道：

if(localName.equalsIgnoreCase("countryBean")){
    isCountryBean = true;
    // other stuff
} else if (localName.equalsIgnoreCase("secutiryQuestion1")){
    isSecurityQuestion1 = true;
    isCountryBean = false;
}

在endElement（...）中检查：

if(localName.equalsIgnoreCase("id")){
    if(isCountryBean){
        tempResponse.setCountryId(currentValue); 
     }
}
if(localName.equalsIgnoreCase("name")){
    if(isCountryBean){
        isCountryBean = false;
        tempResponse.setCountryName(currentValue);

     }
}

为其他最外向的标签做。希望它会对你有所帮助。

Answer 2

您需要维护stack of root nodes。

获取String root类型的变量并保持stack of root element。

内部的startElement方法：

public void startElement(String namespaceURI, String localName, String qName, Attributes atts) throws SAXException,
            IllegalArgumentException
{

   // call to abstract method
   onStartElement(namespaceURI, localName, qName, atts);

   // Keep the trace of the root nodes
   if (root.length() > 0)
   {
    root= root.concat(",");
   }
   root= root.concat(localName);
}

内部endElement方法：

public void endElement(String namespaceURI, String localName, String qName) throws SAXException
{
   // remove the end element from stack of root elements
   int index = root.lastIndexOf(',');
   if (index > 0)
   {
    root= root.substring(0, index);
   }
   onEndElement(namespaceURI, localName, qName);
}

Android：如何在SAX Parser中解析相同的标签？

2 个答案: