Question

其实我正在尝试将hex转换为bin。

a=hex2dec('ab32');  
a=dec2bin(a);
%now I have a 1to1 char array of for example 1010101...
%I want to have an 1*16 array of 1 and 0's

我该怎么做？

Answer 1

你可以这样做：

a=logical(a-'0')

示例：

octave:224> a=hex2dec('ab32')
a =  43826
octave:225> a=dec2bin(a)
a = 1010101100110010
octave:226> a=logical(a-'0')
a =

   1   0   1   0   1   0   1   1   0   0   1   1   0   0   1   0

octave:227> whos a
Variables in the current scope:

   Attr Name        Size                     Bytes  Class
   ==== ====        ====                     =====  ===== 
        a           1x16                        16  logical

Total is 16 elements using 16 bytes

octave:228>

Answer 2

这为你提供了一个1 * 16的实数矢量，都是0或1：

(dec2bin(hex2dec('ab32'))-'0')

虽然这给你一个1 * 16的逻辑向量，都是假的或者是真的（看起来像0和1）

(dec2bin(hex2dec('ab32'))-'0')==1

如何在MATLAB中将'1 * 1 char'转换为逻辑向量？

2 个答案: