使用NSURLRequest时出现错误的URL错误

时间:2012-07-06 12:24:19

标签: objective-c ios cocoa-touch url nsurlrequest

我有下一个创建的NSURLRequest:

NSString *url=[NSString stringWithFormat:@"http://myserveradress.com/api/users/register?register_password=%@&register_password_confirm=%@&register_email=%@&register_terms=1&register_user=%@&process_registration=1&register_name=%@"
                   ,
                   [password stringByReplacingOccurrencesOfString:@" " withString:@"%"],[confirm stringByReplacingOccurrencesOfString:@" " withString:@"%"],[email stringByReplacingOccurrencesOfString:@" " withString:@"%"],[user stringByReplacingOccurrencesOfString:@" " withString:@"%"],[realName stringByReplacingOccurrencesOfString:@" " withString:@"%"]
                   ];
    NSURLRequest *request=[NSURLRequest requestWithURL:[NSURL URLWithString:url]];
    NSError *error;
    NSData *data=[NSURLConnection sendSynchronousRequest:request returningResponse:nil error:&error];
    NSString *result_string = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
    return result_string;

结果字符串为http://myserveradress.ru/api/users/register?register_password=password&register_password_confirm=password&register_email=myname@mail.com&register_terms=1&register_user=myname&process_registration=1&register_name=Artem%Kulikov,错误状态为

Error Domain=NSURLErrorDomain Code=-1000 "bad URL" UserInfo=0x71e62b0 {NSUnderlyingError=0x71e6470 "bad URL", NSLocalizedDescription=bad URL}

在浏览器中链接正常。问题仅在于应用程序。

2 个答案:

答案 0 :(得分:14)

这不是逃避字符串的正确方法,有一种方法,stringByAddingPercentEscapesUsingEncoding:。所以改成它:

NSString *url = [NSString stringWithFormat:@"http://myserveradress.com/api/users/register?register_password=%@&register_password_confirm=%@&register_email=%@&register_terms=1&register_user=%@&process_registration=1&register_name=%@"
                   , password, confirm, email, user, realName];
NSString *properlyEscapedURL = [url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURLRequest *request=[NSURLRequest requestWithURL:[NSURL URLWithString:properlyEscapedURL]];

更不用说空格的正确转义码是%20而不是%

答案 1 :(得分:2)

@ user1506704,你没有使用register_name中的编码方法,register_name中是否有空格或其他特殊字符?使用NSString方法stringByAddingPercentEscapesUsingEncoding:.

您可以尝试转义网址:

- (NSString *)stringByAddingPercentEscapesUsingEncoding:(NSStringEncoding)encoding`