如何从.net Web服务启动应用程序?

时间:2012-07-06 12:01:43

标签: .net web-services process

我使用System.Diagnostic.Process类使用.Net WCF Web服务在我的服务器pc上启动进程。它们开始流畅,我可以看到它们从任务管理器运行,但没有显示窗口。你们怎么认为我能解决这个问题?

3 个答案:

答案 0 :(得分:3)

如果要显示GUI并且用户能够与其进行交互,则必须启动交互式过程。目前可能不是您的网络服务。

请参阅Start a windows service and launch cmd

答案 1 :(得分:1)

你不应该这样做,但是......

您可以在当前会话中以用户身份启动程序

IntPtr UserTokenHandle = IntPtr.Zero;
WTSQueryUserToken ( WTSGetActiveConsoleSessionId(), ref UserTokenHandle);

PROCESS_INFORMATION ProcInfo = new PROCESS_INFORMATION();
STARTUPINFOW StartInfo = new STARTUPINFOW();
StartInfo.cb = Convert.ToUInt32(System.Runtime.InteropServices.Marshal.SizeOf(StartInfo));


CreateProcessAsUser ( UserTokenHandle, @"C:\dir\MyApp.exe",
    IntPtr.Zero,
    IntPtr.Zero,
    IntPtr.Zero,
    false,
    0,
    IntPtr.Zero,
    null,
    ref StartInfo,
    ref ProcInfo);

if (!(UserTokenHandle == IntPtr.Zero))
{
    CloseHandle ( UserTokenHandle);
}

必需的导入和结构:

[DllImport("kernel32.dll", EntryPoint = "WTSGetActiveConsoleSessionId", SetLastError = true)]
public static extern uint WTSGetActiveConsoleSessionId ();

[DllImport("Wtsapi32.dll", EntryPoint = "WTSQueryUserToken", SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
public static extern bool WTSQueryUserToken ( uint SessionId, ref IntPtr phToken );

[DllImport("kernel32.dll", EntryPoint = "CloseHandle", SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
public static extern bool CloseHandle ( [InAttribute()]
    IntPtr hObject );

[DllImport("advapi32.dll", EntryPoint = "CreateProcessAsUserW", SetLastError = true)]
[return: MarshalAs(UnmanagedType.Bool)]
public static extern bool CreateProcessAsUser (
    [InAttribute()]
    IntPtr hToken,
    [InAttribute(), MarshalAs(UnmanagedType.LPWStr)]
    string lpApplicationName, System.IntPtr lpCommandLine,
    [InAttribute()]
    IntPtr lpProcessAttributes,
    [InAttribute()]
    IntPtr lpThreadAttributes,
    [MarshalAs(UnmanagedType.Bool)]
    bool bInheritHandles, uint dwCreationFlags,
    [InAttribute()]
    IntPtr lpEnvironment,
    [InAttribute(), MarshalAsAttribute(UnmanagedType.LPWStr)]
    string lpCurrentDirectory,

ref STARTUPINFOW lpStartupInfo,

ref PROCESS_INFORMATION lpProcessInformation );

[StructLayout(LayoutKind.Sequential)]
public struct SECURITY_ATTRIBUTES
{
    public uint nLength;
    public IntPtr lpSecurityDescriptor;
    [MarshalAs(UnmanagedType.Bool)]
    public bool bInheritHandle;
}

[StructLayout(LayoutKind.Sequential)]
public struct STARTUPINFOW
{
    public uint cb;
    [MarshalAs(UnmanagedType.LPWStr)]
    public string lpReserved;
    [MarshalAs(UnmanagedType.LPWStr)]
    public string lpDesktop;
    [MarshalAs(UnmanagedType.LPWStr)]
    public string lpTitle;
    public uint dwX;
    public uint dwY;
    public uint dwXSize;
    public uint dwYSize;
    public uint dwXCountChars;
    public uint dwYCountChars;
    public uint dwFillAttribute;
    public uint dwFlags;
    public ushort wShowWindow;
    public ushort cbReserved2;
    public IntPtr lpReserved2;
    public IntPtr hStdInput;
    public IntPtr hStdOutput;
    public IntPtr hStdError;
}

[StructLayout(LayoutKind.Sequential)]
public struct PROCESS_INFORMATION
{
    public IntPtr hProcess;
    public IntPtr hThread;
    public uint dwProcessId;
    public uint dwThreadId;
}

答案 2 :(得分:0)

您正在谈论的是Web服务,因此它可能也作为Windows服务运行? 在这种情况下,您可以启动流程,但永远不会看到任何形式。

Windows服务旨在在您的计算机上运行,​​即使没有用户登录也是如此。 因此,它永远不知道在哪里显示您想要运行的应用程序!

您可以使用名为“允许与桌面交互”(或类似内容)的设置,但服务并不意味着以这种方式使用。