Question

假设我有以下代码需要在匿名函数中抛出异常而不修改函数：

FOO.doSomething(new Transactable(){
 public void run(FOO foo) {
     // How to proxy a exception throw
     // from here, without modifying the class
 }
});

像：

@Override
public void run() throws MyCustomException{
       FOO.doSomething(new Transactable(){
           public void run(FOO foo) {
               // How to proxy a exception throw
               // from here, without modifying the class
           }
        });             
}

Answer 1

我怀疑我是否理解这一点，但这是我的镜头。我想你试图以某种方式从匿名类移动异常并从父方法中抛出它：

class ExceptionWrapper {
    public Exception exception;
}

@Override
public void run() throws MyCustomException{
       final ExceptionWrapper ew = new ExceptionWrapper();

       FOO.doSomething(new Transactable(){
           public void run(FOO foo) {
               try {
                   ...
               } catch(MyCustomException ex) {
                   ew.exception = ex;
               }
           }
        });             

        if(ew.exception != null) throw (MyCustomException)ew.exception;
}

代理“抛出异常”

1 个答案: