Question

我有一些html代码，我想在某些时候替换它。

如

NSString *stringSHOW = @"width="353" height="500" width="131" height="204" width="777" width="369" width="888"/>";

像这样的东西。但我想替换所有[ width="any" to width="300" ]。

有没有办法做到这一点？

Answer 1

查看NSRegularExpression的文档和采用正则表达式的NSString方法。

Answer 2

NSString *newStringShow = [stringShow stringByReplacingOccurrencesOfString:@"any"withString:@"300"];

Answer 3

- (NSString *)updateString:(NSString *)inputString withString:(NSString *)stringToReplace {

    NSArray *components = [inputString componentsSeparatedByString:@" "];
    NSMutableArray *mutableComponents = [[components mutableCopy] autorelease];

    for (NSString *componentString in components) {

        NSMutableString *mutableString = [[componentString mutableCopy] autorelease];
        NSRange replaceRangeFirstOccurenceStart = [mutableString rangeOfString:@"width=\""];
        if (replaceRangeFirstOccurenceStart.location == NSNotFound) {
            NSLog(@"String not found in component");
        }
        NSMutableString *replaceString = [NSMutableString string];
        for (int i = 0; i < replaceRangeFirstOccurenceStart.length; i ++) {
            [replaceString appendString:@"_"];
        }
        NSMutableString *modifiedString = [mutableString stringByReplacingCharactersInRange:replaceRangeFirstOccurenceStart withString:replaceString];
        NSRange replaceRangeEnd = [modifiedString rangeOfString:@"\""];
        NSRange rangeToChange = NSMakeRange(replaceRangeFirstOccurenceStart.length - 1, replaceRangeEnd.location + replaceRangeEnd.length - replaceRangeFirstOccurenceStart.length + 1);        
        NSString *updatedString = [mutableString stringByReplacingCharactersInRange:rangeToChange withString:[NSString stringWithFormat:@"\"%@\"", stringToReplace]];
        [mutableComponents replaceObjectAtIndex:[components indexOfObject:componentString] withObject:updatedString];
    }
    return [mutableComponents componentsJoinedByString:@" "];
}

NSString *stringShow = @"width=\"355\" width=\"200\"";
[self updateString:stringShow withString:@"34501"];

你也可以发送params作为参数字符串，在你的情况下@“width = \”“和@”\“”，以使这个方法完全抽象，并能够替换你传递的任何东西。

iOS：有没有办法替换大致相同的字符串？

3 个答案: