在父JPanel中显示添加的JPanel

Question

如何在父JPanel内看到添加的JPanel？

我正在使用Netbeans来设计我的UI。

我有一个MainFrame.java，其中包含两个面板;即headerPanel和bodyPanel。

在headerPanel我已经放了三个按钮，让它为button1，button2和button3。

此外，我创建了三个单独的文件JPanel，将其命名为panel1，panel2和panel3。

然后我在bodypanel的{​​{1}}内的构造函数中添加了我的所有三个面板。

MainFrame.java

我希望点击相应的按钮时，只有相应的面板应显示在主机的bodyPanel.add(panel1); bodyPanel.add(panel2); bodyPanel.add(panel3); 中，即如果我点击bodypanel，则应显示button1。

我已经在panel1鼠标侦听器方法中尝试了以下代码：

button1

但bodyPanel.validate(); bodyPanel.getComponent(0).setVisible(true); 没有出现。我这样做是因为面板中添加的组件被分配了索引。所以首先我尝试获取组件然后使其可见。它不起作用。

Answer 1

使用CardLayout，如图here所示。

Answer 2

您的要求完全由CARD LAYOUT填写 see this example link

and below example Link

问题案例的完美代码是

package panels.examples;

import java.awt.BorderLayout;
import java.awt.CardLayout;
import java.awt.Color;
import java.awt.Container;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JPanel;

public class MainFrame extends JFrame implements ActionListener
{
JPanel headerPanel;
JPanel bodyPanel;
JPanel panel1,panel2,panel3;
JButton button1,button2,button3;
Container con;
CardLayout clayout;
public MainFrame() 
{
    //con=getContentPane();
    clayout=new CardLayout();
    headerPanel=new JPanel();
    bodyPanel=new JPanel(clayout);

    button1=new JButton("button1");
    button2=new JButton("button2");
    button3=new JButton("button3");

    //add three buttons to headerPanel
    headerPanel.add(button1);
    headerPanel.add(button2);
    headerPanel.add(button3);

    button1.addActionListener(this);
    button2.addActionListener(this);
    button3.addActionListener(this);

    panel1=new JPanel();
    panel1.add(new JLabel("Panel1"));
    panel1.setBackground(Color.pink);
    panel2=new JPanel();
    panel2.add(new JLabel("Panel2"));
    panel2.setBackground(Color.gray);
    panel3=new JPanel();
    panel3.add(new JLabel("Panel3"));

    //add above three panels to bodyPanel
    bodyPanel.add(panel1,"one");    
    bodyPanel.add(panel2,"two");    
    bodyPanel.add(panel3,"three");  


    setLayout(new BorderLayout());
    setSize(600,450);
    add(headerPanel,BorderLayout.NORTH);
    add(bodyPanel,BorderLayout.CENTER);
//  headerPanel.setBounds(0,0,600,100);
    bodyPanel.setBounds(0,100, 600, 500);
    setVisible(true);

}

public static void main(String args[])
{
    new MainFrame();
}

@Override
public void actionPerformed(ActionEvent e) {

    if(e.getSource()==button1)
    {
        clayout.show(bodyPanel, "one");
    }
    else if(e.getSource()==button2)
    {
        clayout.show(bodyPanel, "two");
    }
    else if(e.getSource()==button3)
    {
        clayout.show(bodyPanel, "three");
    }

}

}

out put

Answer 3

使用CardLayout。下面是我写的助手课程。希望它有所帮助。

import java.awt.CardLayout;

import javax.swing.JPanel;

/**
 * 
 * @author Dchan(Dulitha Wijewantha)
 * 
 *         This class is used to switch Cards in a CardLayout
 * 
 * @version $Revision: 1.0 $
 */
public class CardLayoutHelper {

    private JPanel panel;
    private CardLayout layout;

    /**
     * 

     * @param panel JPanel
     */
    public CardLayoutHelper(JPanel panel) {
        this.panel = panel;
        this.layout = (CardLayout) this.panel.getLayout();
    }
    public CardLayoutHelper(JPanel panel, JPanel... panels){
        this(panel);
        for (int i = 0; i < panels.length; i++) {
            JPanel jPanel = panels[i];
            panel.add(jPanel.getName(), jPanel);
        }
    }

    /**
     * 
     * @param currentPanel
     *            - The panel that will be switched into the view
     */
    public void switchPanel(JPanel currentPanel) {
        panel.removeAll();
        panel.add(currentPanel, currentPanel.getName());
        layout.show(panel, currentPanel.getName());
        panel.revalidate();
        panel.repaint();
    }
    public void switchPanel(String name){
        layout.show(panel, name);
        panel.revalidate();
        panel.repaint();
    }
}