Question

我做了一个简单的评论系统here，我想创建一个删除按钮，如果按下该注释将被删除（基本上从数据库中删除）。我不知道如何在评论中实现这一点。我已经使javascript与delta.php进行交互，但我不知道如何制作delete.php。 mySQL字段是;

我，
姓名，
Url，
电子邮件和
身体

如何编写delete.php以与mySQL和评论系统进行交互？谢谢！

<script type="text/javascript">
    function deleteUser(id){
    new Ajax.Request('delete.php', {
        parameters: $('idUser'+id).serialize(true),
    });
}
</script>

Answer 1

您可以使用jquery简化操作：

$('#delete_button').click(function(){
   var comment_id = $(this).attr('id');//you should use the id of the comment as id for the delete button for this to work.
   $.post('delete.php', {'comment_id' : comment_id}, function(){
      $(this).parent('div').remove(); //hide the comment from the user
   });
});

delete.php将包含以下内容：

<?php
//include database configuration file here. 
//If you don't know how to do this just look it up on Google.

$comment_id = $_POST['comment_id'];

mysql_query("DELETE comment from TABLE WHERE comment_id='$comment_id'");
//mysql_query is not actually recommended because its already being deprecated. 
//I'm just using it for example sake. Use pdo or mysqli.  
?>

Answer 2

以下是一个例子：

<强>的Javascript ：

function deleteComment(id)
{
    $.ajax(
    {
        type: "POST",
        url: "delete.php?id="+id,
        dataType: "html",
        success: function(result)
        {
            if(result == "Ok") alert("The comment is successfuly deleted");
            else alert("The following error is occurred: "+result);
        }
    });
}

PHP（delete.php）：

if(!isset($_POST['id'])) die("No ID specified");
$id = mysql_real_escape_string($_POST['id']);

mysql_query("DELETE FROM `comments` WHERE `id` = $id") or die(mysql_error());

echo "Ok";

使用ajax，php和javascript删除mySQL记录

2 个答案: