所以我有两个从数据库读取数据并将数据写入字符串的游标,但即使数据库存储了数据,游标也总是为空。我检查了SQLite管理器,该数据库包含存储的数据。 Log Cat表示名为“IF1”和“IF2”的日志已执行。 这是我的代码,我希望有人能找到什么问题。
String var;
final TextView t = (TextView) findViewById(R.id.textView2);
final TextView t2 = (TextView) findViewById(R.id.textView3);
Intent intent = getIntent();
var = intent.getStringExtra("datum");
SQLiteDatabase db = openOrCreateDatabase ("MyDB", MODE_PRIVATE, null);
String q =" SELECT COALESCE (znak, '') as znak,COALESCE (sprava, '') as sprava, COALESCE(serija, '') as serija, COALESCE(podatak, '') as podatak, COALESCE(ponavljanja, '') as ponavljanja, vrijeme FROM tablica WHERE vrijeme LIKE '"+ var + "'" ;
Cursor c = db.rawQuery(q, null);
String xy = "SELECT vrijeme FROM tablica WHERE vrijeme LIKE '"+ var + "'";
Cursor dd = db.rawQuery(xy, null);
if (dd.getCount() < 1) {
Log.d("LIST.DETAILS", "IF1");
dd.close();
db.close();
Toast.makeText(NapredakActivity.this, "Empty!", Toast.LENGTH_SHORT).show();
startActivity(new Intent(this, calendar.class));
} else {
String i = "";
dd.moveToFirst();
String st2 = dd.getString(dd.getColumnIndex("vrijeme"));
i = "Datum:" +"\t" + st2;
t2.setText(i);
dd.close();
}
if (c.getCount() < 1) {
Log.d("LISTA.DETALJI", "IF2");
c.close();
db.close();
Toast.makeText(NapredakActivity.this, "Empty!", Toast.LENGTH_SHORT).show();
startActivity(new Intent(this, calendar.class));
} else {
String j = "";
c.moveToFirst();
do {
String cm55 = c.getString(c.getColumnIndex("sprava"));
String cm = c.getString(c.getColumnIndex("serija"));
String cm2 = c.getString(c.getColumnIndex("podatak"));
String cm3 = c.getString(c.getColumnIndex("ponavljanja"));
String cm_znak = c.getString(c.getColumnIndex("znak"));
j = j +cm55+ "\n" + cm + "\t" +cm2 +cm_znak + cm3 ;
} while (c.moveToNext());
t.setText(j);
c.close();
db.close();
}
答案 0 :(得分:1)
我相信你缺少WHERE子句中的通配符:
"vrijeme LIKE '%"+ var + "%'"
否则:
"vrijeme LIKE '"+ var + "'"
与:
相同"vrijeme = '"+ var + "'"
另外我猜测英语不是你的第一语言,但你的变量名字非常神秘。考虑使用更具描述性的名称,它只是有助于您的代码的可读性。