Question

假设我有以下几个字段：

abd738927
jaksm234234
hfk342
ndma0834
jon99322

输入：varchar。

如何仅显示此数值以显示：

尝试过子串，但数据的长度不一样，由于无法转换，任何想法都无法投射？

Answer 1

以下是PATINDEX的示例：

select SUBSTRING(fieldName, PATINDEX('%[0-9]%', fieldName), LEN(fieldName))

这假定（1）字段将具有数字，（2）数字全部组合在一起，以及（3）数字后面没有任何后续字符。

Answer 2

如果你不想创建一个函数，你可以这样：

cast(replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(
replace(replace(replace(replace(replace(replace(replace(replace(replace(replace(
replace(replace(replace(replace(replace(replace(replace(replace(replace(YOUR_COLUMN
,'A',''),'B',''),'C',''),'D',''),'E',''),'F',''),'G',''),'H',''),'I',''),'J','')
,'K',''),'L',''),'M',''),'N',''),'O',''),'P',''),'Q',''),'R',''),'S',''),'T','')
,'U',''),'V',''),'W',''),'X',''),'Y',''),'Z',''),'$',''),',',''),' ','') as float)

Answer 3

DECLARE @NonNumeric varchar(1000) = 'RGI000Testing1000'
DECLARE @Index int  
SET @Index = 0  
while 1=1  
begin  
    set @Index = patindex('%[^0-9]%',@NonNumeric)  
    if @Index <> 0  
    begin  
        SET @NonNumeric = replace(@NonNumeric,substring(@NonNumeric,@Index, 1), '')  
    end  
    else    
        break;   
end     
select @NonNumeric -- 0001000

Answer 4

仅提取数字（不使用while循环）并检查每个字符以查看它是否为数字并将其提取

   Declare @s varchar(100),@result varchar(100)
    set @s='as4khd0939sdf78' 
    set @result=''

    select
        @result=@result+
                case when number like '[0-9]' then number else '' end from 
        (
             select substring(@s,number,1) as number from 
            (
                select number from master..spt_values 
                where type='p' and number between 1 and len(@s)
            ) as t
        ) as t 
    select @result as only_numbers

Answer 5

我认为你想要VBA的Val()功能。使用IsNumeric()

可以轻松完成

create function Val 
(
    @text nvarchar(40)
) 
returns float
as begin
    -- emulate vba's val() function
    declare @result float 
    declare @tmp varchar(40)

    set @tmp = @text
    while isnumeric(@tmp) = 0 and len(@tmp)>0 begin
        set @tmp=left(@tmp,len(@tmp)-1)
    end
    set @result = cast(@tmp as float)

    return @result
end

Answer 6

input table

如果图像中有如上所示的数据，请使用以下查询

select field_3 from table where PATINDEX('%[ ~`!@#$%^&*_()=+\|{};",<>/?a-z]%', field_3)=0

结果将如下所示

Result table

Answer 7

select substring(
                'jaksm234234',
                patindex('%[0-9]%','jaksm234234'),
                LEN('jaksm234234')-patindex('%[0-9]%','jaksm234234')+2
                )

Answer 8

仅提取字符串中的数字。返回包含所有数字的字符串。示例：this1is2one345long6789number将返回123456789

CREATE FUNCTION [dbo].[GetOnlyNumbers] (@Temp VARCHAR(1000))

RETURNS VARCHAR (1000) AS BEGIN

    DECLARE @KeepValues AS VARCHAR(50)
    SET @KeepValues = '%[^0-9]%'
    WHILE PATINDEX(@KeepValues, @Temp) > 0
        SET @Temp = STUFF(@Temp, PATINDEX(@KeepValues, @Temp), 1, '')

    RETURN @Temp
END

SQL只接受varchar中的数值

8 个答案: