Question

我有2张表格如下

client_table
 date (timestamp)
 ip (varchar)
 value1 (int)
 value2 (int)

ip_address_table
 starting_ip (varchar)
 ending_ip (varchar)
 provider (varchar)

我正在尝试使用ip_address_table表查找client_table条目，以查找ip地址在范围内的每小时平均值。（如果它不在范围内忽略该行）以下是我的想法

SELECT avg(value1),avg(value2)
FROM client_table
WHERE (INET_ATON(ip) BETWEEN INET_ATON(starting_ip) AND INET_ATON(ending_ip))
GROUP BY DATE(date),HOUR(date)

但是，它没有给出正确的输出。我看了http://blog.jcole.us/2007/11/24/on-efficiently-geo-referencing-ips-with-maxmind-geoip-and-mysql-gis/但是很难写出一个存储函数来简化任务任何帮助赞赏

由于

编辑：我的样本数据低于

client_table
"date"  "ip"    "value1"    "value2"
"2012-01-10 06:38:29"   "121.1.2.3" "1049"  "301"
"2012-01-11 06:41:35"   "58.1.2.3"  "16453" "794"
"2012-01-12 06:43:50"   "101.1.2.3" "1712"  "410"
"2012-01-13 06:44:04"   "121.1.10.3"    "6594"  "863"
"2012-01-14 06:45:00"   "79.1.2.3"  "879"   "614"

ip_address_table
"starting_ip" "ending_ip" "provider"
"121.0.0.0" "121.255.255.255" provider1
"79.1.2.0" "79.1.2.255" provider1
....

Answer 1

我没有看到你正在使用ip表，也许尝试这样的事情（未经测试）：

SELECT avg(value1),avg(value2)
FROM client_table c, ip_address_table ip
WHERE (INET_ATON(ip) BETWEEN INET_ATON(starting_ip) AND INET_ATON(ending_ip))
GROUP BY DATE(date),HOUR(date)

mysql从另一个具有ip范围的表中查找ip地址

1 个答案: