PHP elseif语句

Question

我正在使用PHP浏览器检测并希望使用else if语句将它们重定向到依赖于浏览器的不同页面或包含某个文件..现在我正在采样重定向。

我收到语法错误，我很困惑，为什么，这是代码：

if($browser['name'] . $browser['version'] == "firefox" . "13.0.1"){
    header("Location: newff.php");
  elseif($browser['name'] . $browser['version'] != "firefox" . "13.0.1"){
    header("Location: oldff.php");
  } elseif($browser['name'] . $browser['version'] == "msie" . "13.0.1") {
    header("Location: newie.php");
  } elseif($browser['name'] . $browser['version'] != "msie" . "13.0.1") {
    header("Location: oldie.php");
  } elseif($browser['name'] . $browser['version'] == "chrome" . "20.0.1132.47"){
    header("Location: newchrome.php");
  } elseif($browser['name'] . $browser['version'] != "chrome" . "20.0.1132.47"){
    header("Location: oldchrome.php");
  } elseif($browser['name'] . $browser['version'] == "safari" . "534.57.2"){
    header("Location: newsafari.php");
  } elseif($browser['name'] . $browser['version'] != "safari" . "534.57.2") {
    header("Location: oldsafari.php");
  } else {
    header("Location: other.php");
  }

由于

本

Answer 1

如果出现以下情况，您首先忘记使用右手曲柄：

if($browser['name'] . $browser['version'] == "firefox" . "13.0.1") {
    header("Location: newff.php");
} // this is missing