如何为UIViewController
转换此内容是可能的:
for (UIViewController *tmpController in [self.navigationController viewControllers])
{
if ([tmpController isKindOfClass:[RootViewController class]])
{
[self.navigationController popToViewController:tmpController animated:YES];
break;
}
}
[self.navigationController viewControllers]
- >如何为UIViewController
转换此内容,因为我遇到了错误,
[self.navigationController popToViewController:tmpController animated:YES];
- >而这部分我把它转换成这个 - > [self dismissModalViewControllerAnimated:YES];
答案 0 :(得分:1)
如果您有ViewController A,它提供了呈现ViewController C的ViewController B
你想回到A,在viewController C中执行以下操作
[self dismissModalViewControllerAnimated:NO];
[[self presentingViewController] dismissModalViewControllerAnimated:NO];
答案 1 :(得分:0)
您可以按如下方式获取视图层次结构:
for(UIView *view in [self.view subviews])
答案 2 :(得分:0)
从上面的评论中我觉得你呈现的控制器如从A到B和从B到C。
现在你想要从C到A来做那个使用下面的代码
[self.navigationController popToRootViewControllerAnimated:YES];
修改强>
//Try this.
[[[self parentViewController] parentViewController] dismissModalViewControllerAnimated:YES];