Question

    <script type="text/javascript" src="http://www.google.com/jsapi?key=asedAWWefefI-43WqNAiw0XkfflwpU9zqkg">
            </script>
            <script type="text/javascript">
                google.load("jquery", "1.6.1");
            </script><script src="http://code.jquery.com/jquery-latest.js"></script>
            <script type="text/javascript">
                google.setOnLoadCallback(function()
                {...
}....

我的代码无法正常工作我猜这是上面代码的错误。

整个代码

<!DOCTYPE html>
<html lang="en">
    <head>
        <meta charset="utf-8" />
        <title></title>
        <script type="text/javascript" src="http://www.google.com/jsapi?key=AIzaSyDzbTUhnU2I-erwerwe3450XkfflwpU9zqkg">
        </script>
        <script type="text/javascript">
            google.load("jquery", "1.6.1");
        </script><script src="http://code.jquery.com/jquery-latest.js"></script>
        <script type="text/javascript">
            google.setOnLoadCallback(function()
            {
                $(function()
                {
                    $('#catalog').click(function(e)
                    {
                        e.preventDefault();
                        $.getJSON('books.php', function(data) {   
                            var book = "<h3>" + data.title + </h3>";                             
                            book += "<p>ISBN: " + data.isbn + "</p>";                                                
                            book += "<br/>Published Date: " + data.publishDate;
                            book += "<br/>Publisher: " + data.publisher;
                            var author = [];

                            $.each(data.authors, function(i, ov) {
                                authors.push(ov.name)
                            });

                            book += "<br/>Authors: " + authors.join(", ");
                            $('#resopnse').html(book);
                                                                                                                                            });
                    });
                });
            });                                              
        </script>
    </head>
    <body>
        <p><a id="catalog" href="">Retrieve book information</a></p>
        <div id="response"></div>
    </body>
</html>

当我点击链接时它没有显示任何内容。我已经有一个books.php文件，其数组格式化为具有json输出。

更新

$.getJSON('books.php', function(data)
                        {
                            var book = "<h3>" + data.title + "</h3>";
                            book += "<p>ISBN: " + data.isbn + "</p>";
                            book += "<br/>Published Date: " + data.publishDate;
                            book += "<br/>Publisher: " + data.publisher;
                            var author = [];
                            $.each(data.authors, function(i, ov) { authors.push(ov.name) });
                            book += "<br/>Authors: " + authors.join(", ");
                            $('#response').html(book);

                        });

此功能无法进入内部。

Answer 1

您的网页上有一个javascript错误。你应该真的使用调试器。 Chrome开发工具非常棒。如果您使用的是铬或菜单，请按[ctr] [shift] [j]＆gt;工具＆gt; js console

var book = "<h3>" + data.title + </h3>";

缺少“

显示数组的内容

1 个答案: