Question

我有linq请求。我需要在select中获取item.Title。怎么做？

var list = (from item in answer.SubItems.OfType<TItemView>()
            where item.SubItems != null
            from ty in item.SubItems
            select ty as TDealRequestView
                into request
                select new
                {
                    itemTitle = item.Title,//item not visible 
                    Title = request.Title,

                }).ToList();

Answer 1

您可以使用关键字：let

in order to initialize your value request.Title

let request = your treatment... (request is local variable of your query)

Answer 2

现在无法检查，但请尝试：

String title;

var list = (from item in answer.SubItems.OfType<TItemView>()
        where item.SubItems != null
        let title=item.title 
        ...

        //now use title

Answer 3

替换：

select ty as TDealRequestView
            into request

使用：

let request = ty as TDealRequestView

如何在下面的查询中传递变量

3 个答案: