Question

我正在尝试创建一个用于ArrayAdapter的自定义ListFragment。现在ListFragment中没有显示任何内容，只有TextView表示它是什么片段编号。我在我的适配器的getView()方法中放了一个断点，但它没有被调用。我搜索了无法调用的原因，有些人似乎认为我的ListView被隐藏了，所以我尝试将layout_height更改为wrap_content，但这不起作用。

此外，我一直在关注此开发人员页面中的代码：http://developer.android.com/reference/android/support/v4/app/FragmentPagerAdapter.html

ListFragment：

public class HomeFragment extends ListFragment implements FragmentTitle
{
private int mNum = 0;
private String mTitle = "Home";
private ListView mListView;
private MyArrayAdapter mAdapter;

@Override
public void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
    mNum = getArguments() != null ? getArguments().getInt("num") : 1;
    InfoContainer temp = new InfoContainer("test1", "test2");
    mAdapter = new MyArrayAdapter(getActivity(), android.R.id.list, temp);
}

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) 
{
    View v1 = inflater.inflate(R.layout.fragment_pager_list, container, false);
    TextView tv = (TextView) v1.findViewById(R.id.text);
    tv.setText("Fragment #" + mNum);
    mListView = (ListView) v1.findViewById(android.R.id.list);
    return v1;
}

@Override
public void onActivityCreated(Bundle savedInstanceState) 
{
    super.onActivityCreated(savedInstanceState);
    mListView.setAdapter(mAdapter);
}

@Override
public void onListItemClick(ListView l, View v, int position, long id) 
{
    Log.i("HomeFragment", "Item clicked: " + id);
}

public CharSequence getTitle() 
{
    return mTitle;
}

}

ArrayAdapter：

public class MyArrayAdapter extends ArrayAdapter<InfoContainer>
{
Context mContext;
InfoContainer data;

public MyArrayAdapter(Context context, int textViewResourceId, InfoContainer temp) 
{
    super(context, textViewResourceId);
    mContext = context;
    this.data = temp;
}

@Override
public View getView(int position, View convertView, ViewGroup parent)
{
    View row = convertView;
    ViewHolder holder = new ViewHolder();

    if(row == null)
    {
        LayoutInflater inflater = ((Activity)mContext).getLayoutInflater();
        row = inflater.inflate(R.id.pager, parent, false);
        holder.v1 = (TextView) row.findViewById(R.id.listview_name);
        holder.v2 = (TextView) row.findViewById(R.id.listview_data);
        row.setTag(holder);
    }
    else
    {
        holder = (ViewHolder) row.getTag();
    }
    InfoContainer info = data;
    holder.v1.setText(info.name);
    holder.v2.setText(info.text);
    return row;
}

public static class ViewHolder
{
    TextView v1;
    TextView v2;
}

}

fragment_pager_list.xml：

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:background="#000000" >

<TextView
    android:id="@+id/text"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:gravity="center_vertical|center_horizontal"
    android:text="@string/hello_world"
    android:textAppearance="?android:attr/textAppearanceMedium"
    android:textColor="#FFFFFF" />

    <ListView
        android:id="@android:id/list"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:drawSelectorOnTop="false"
        android:background="@drawable/listview_background"
        android:textColor="#FFFFFF" />

之前我已经制作了自定义ArrayAdapter，没有任何问题，那么我是否缺少让他们使用ListFragment的东西？

Answer 1

解决方案是getCount()为我的ArrayAdapter返回0。所以我只使用mAdapter.add(temp)然后使用mAdapter.notifyDataSetChanged()并且它有效。我还必须将行row = inflater.inflate(R.id.pager, parent, false);更改为row = inflater.inflate(R.layout.listview_row, parent, false);

ListFragment中的自定义ArrayAdapter

1 个答案: