Question

我正在尝试对此页面上的数据进行排序：http://www.excelwrestling.com/sortbymostwinsbyweight.php

我希望按重量排序表格，然后在该重量下获得最多胜利的名称。另外，我想再增加一列，显示该摔跤手获胜的次数。

这是我从教程中看到的，但它们没有被正确排序：

$query="SELECT *,Winner, COUNT(*) as count FROM results GROUP BY Winner ORDER BY Weight ASC ";
$result=mysql_query($query);

谢谢！

Answer 1

SELECT ww.*
FROM 
        ( SELECT Weight, Winner, COUNT(*) AS Wins 
          FROM results 
          GROUP BY Weight, Winner 
        ) AS ww
    JOIN
        ( SELECT DISTINCT Weight
          FROM results
        ) AS dw
            ON  ww.Weight = dw.Weight
            AND ww.Winner =
                ( SELECT r.Winner
                  FROM results AS r
                  WHERE r.Weight = dw.Weight
                  GROUP BY r.Winner 
                  ORDER BY COUNT(*) DESC
                  LIMIT 1
                ) ;

(Weight, Winner)上的索引将有助于提高查询效率。

您也可以通过此查询获得正确的结果，但我不建议使用它，因为它使用了MySQL的一些非标准功能和行为，因此将来可能会中断：

SELECT Weight, Winner, Wins
FROM 
        ( SELECT Weight, Winner, COUNT(*) AS Wins 
          FROM results 
          GROUP BY Weight, Winner 
          ORDER BY Weight, Wins DESC
        ) AS ww
GROUP BY Weight ;

Answer 2

当你说你的要求是“最多的胜利”时，你只是按winner订购。这意味着你应该：

SELECT ...
FROM ...
GROUP BY Winner
ORDER BY Weight ASC, count DESC
         ^^^^^^^^^^^^^---- order by the aggregate results.

请注意，我假设您希望权重按升序排列，并按降序获胜。

mySQL Count Content和自动+1

2 个答案: