我有这个问题:
SELECT a.apartment_id, a.building_id, a.apartment_num, a.floor, at.app_type_desc_en AS app_type_desc,
(SELECT ROW(e.e_name, ot.otype_desc_en)
FROM TABLE_TENANTS t INNER JOIN TABLE_OWNERSHIP_TYPES ot ON ot.otype_id=t.ownership_type INNER JOIN TABLE_ENTITIES e ON
t.entity_id = e.entity_id
WHERE a.apartment_id = t.apartment_id AND t.building_id = a.building_id
ORDER BY t.ownership_type DESC LIMIT 1
) AS t_row
FROM TABLE_APARTMENTS a INNER JOIN TABLE_APPARTMENT_TYPES at ON at.app_type_id = a.apartment_type LEFT OUTER JOIN TABLE_TENANTS t ON a.building_id = t.building_id AND t.entity_id=1 AND t.status=true LEFT OUTER JOIN TABLE_COMMITTEE_DELEGATE cd ON
a.building_id = cd.building_id AND cd.entity_id=1 AND cd.status=true
WHERE a.building_id = 1 AND (t.entity_id=1 OR cd.entity_id=1)
ORDER BY a.apartment_num ASC
当我使用PHP读取结果时,我使用:
while($ap = pg_fetch_array($_qry)){
}
并尝试读取“e_name”,它是ROW(e.e_name)的一部分,但我无法成功。
需要你的想法......拜托。