Question

我在游戏中有一个车轮控制器，其设置如下：

- (void)ccTouchesMoved:(NSSet *)touches withEvent:(UIEvent *)event
{
    UITouch *touch = [touches anyObject];
    CGPoint location = [touch locationInView:[touch view]];
    location = [[CCDirector sharedDirector] convertToGL:location];

    if (CGRectContainsPoint(wheel.boundingBox, location))
    {
        CGPoint firstLocation = [touch previousLocationInView:[touch view]];
        CGPoint location = [touch locationInView:[touch view]];

        CGPoint touchingPoint = [[CCDirector sharedDirector] convertToGL:location];
        CGPoint firstTouchingPoint = [[CCDirector sharedDirector] convertToGL:firstLocation];

        CGPoint firstVector = ccpSub(firstTouchingPoint, wheel.position);
        CGFloat firstRotateAngle = -ccpToAngle(firstVector);
        CGFloat previousTouch = CC_RADIANS_TO_DEGREES(firstRotateAngle);

        CGPoint vector = ccpSub(touchingPoint, wheel.position);
        CGFloat rotateAngle = -ccpToAngle(vector);
        CGFloat currentTouch = CC_RADIANS_TO_DEGREES(rotateAngle);

        wheelRotation += (currentTouch - previousTouch) * 0.6; //limit speed 0.6
    }
}

我通过执行以下操作更新了更新方法中滚轮的旋转：

wheel.rotation = wheelRotation;

现在，一旦用户放开方向盘，我希望它旋转回原来的位置，但不是没有考虑用户滑动的速度。这是我真的无法理解的一点。因此，如果滑动产生大量的速度，那么轮子将继续沿该方向移动，直到将车轮拉回到起始位置的整体力量开始。

任何想法/代码段？

Answer 1

限制车轮旋转+ = currentTouch - previousTouch;
我的意思是

if (currentTouch - previousTouch > wantedLimit) {
wheelrotation += wantedLimit;
}
else {
wheelrotation += currentTouch - previousTouch;
}

旋转轮，触摸加速度

1 个答案: