Question

这是用户邀请代码的片段。代码应该从以前的POST表单中获取电子邮件地址，然后检查它是否格式正确。我使用了一个名为checkMail的函数来完成工作。但是，似乎每当电子邮件格式错误或表单留空时它都不会显示此行：

else if(checkEmail($_POST['email'])==false){ 'Whoops! Looks like the email address you selected is invalid :('; }

或

else { 'Whoops! It looks like you didn&#39;t actually add an email address...'; }

已经卡住了几个小时，试图调试......希望有人在这里可以帮助我！

以下是完整代码：

if(!empty($_POST['email'])) {
        if(checkEmail($_POST['email'])==true) {
            $thisDomain = str_replace('www.', '', $_SERVER['HTTP_HOST']);
            $mailcont = "Someone has invited you to an invite only website!\nYour invite code is: ".$_POST['code'].".\n\nYou can use it at http://".$thisDomain."?go=register&hash=".$_POST['code'];
            if(sendEmail($_POST['email'],'You have been invited!',$mailcont,'noreply@'.$thisDomain)) {
                echo 'Your invite was dispatched to '.$_POST['email'].'<br /><br />Go back <a href="?go=home">home</a>';
            } else { echo 'Whoops! Something went horribly wrong, and we couldn&#39;t send the email :('; }
        } else if(checkEmail($_POST['email'])==false){ 'Whoops! Looks like the email address you selected is invalid :('; }
    } else { 'Whoops! It looks like you didn&#39;t actually add an email address...'; }
break;

以下是函数checkMail的代码：

function checkEmail($email) 
   /**
Validate an email address.
Provide email address (raw input)
Returns true if the email address has the email 
address format and the domain exists.
*/
{
   $isValid = true;
   $atIndex = strrpos($email, "@");
   if (is_bool($atIndex) && !$atIndex)
   {
      $isValid = false;
   }
   else
   {
      $domain = substr($email, $atIndex+1);
      $local = substr($email, 0, $atIndex);
      $localLen = strlen($local);
      $domainLen = strlen($domain);
      if ($localLen < 1 || $localLen > 64)
      {
         // local part length exceeded
         $isValid = false;
      }
      else if ($domainLen < 1 || $domainLen > 255)
      {
         // domain part length exceeded
         $isValid = false;
      }
      else if ($local[0] == '.' || $local[$localLen-1] == '.')
      {
         // local part starts or ends with '.'
         $isValid = false;
      }
      else if (preg_match('/\\.\\./', $local))
      {
         // local part has two consecutive dots
         $isValid = false;
      }
      else if (!preg_match('/^[A-Za-z0-9\\-\\.]+$/', $domain))
      {
         // character not valid in domain part
         $isValid = false;
      }
      else if (preg_match('/\\.\\./', $domain))
      {
         // domain part has two consecutive dots
         $isValid = false;
      }
      else if
(!preg_match('/^(\\\\.|[A-Za-z0-9!#%&`_=\\/$\'*+?^{}|~.-])+$/',
                 str_replace("\\\\","",$local)))
      {
         // character not valid in local part unless 
         // local part is quoted
         if (!preg_match('/^"(\\\\"|[^"])+"$/',
             str_replace("\\\\","",$local)))
         {
            $isValid = false;
         }
      }
      if ($isValid && !(checkdnsrr($domain,"MX") || 
 checkdnsrr($domain,"A")))
      {
         // domain not found in DNS
         $isValid = false;
      }
   }
   return $isValid;
}

先谢谢你们。你们很棒，我是stackoverflow的新手，但我发现自己每天都会回到这里寻找想法和社区的大力帮助！

Answer 1

else { 'Whoops! It looks like you didn't actually add an email address...'; } 应该 else { echo 'Whoops! It looks like you didn't actually add an email address...'; }

Answer 2

这是检查电子邮件地址的简短方法。

<?php
$re1='.*?'; //Non-greedy match on filler
$re2='([\\w-+]+(?:\\.[\\w-+]+)*@(?:[\\w-]+\\.)+[a-zA-Z]{2,7})'; //Email Address 1
if ($c=preg_match_all ('/'.$re1.$re2.'/is', $text, $matches)) {
    $email=$matches[1][0];
}
?>

$email将包含$text内的电子邮件或任何内容。您可以稍后查看empty()。在我看来，域验证毫无意义。你可以说你想要的所有有趣的令人印象深刻的东西，我还没有看到一个现实世界的情况，这样的支票是必要的。

验证电子邮件格式PHP

2 个答案: