我通过(简化)运行嵌入式ipython控制台:
# the code uses PyQt4, this makes sure it is initialized properly
import IPython.lib.inputhook
qapp=IPython.lib.inputhook.enable_gui(gui='qt4')
# create the embedded terminal
from IPython.frontend.terminal.embed import InteractiveShellEmbed
ipshell=InteractiveShellEmbed()
ipshell()
如果我想运行ipython的Qt console而不是嵌入式终端shell,那么这段代码会是什么样子?有一些使用ipython qtconsole
的例子,但不是如何将它集成到我自己的代码中。
答案 0 :(得分:0)
在此问题中有一个示例脚本:Embedding IPython Qt console in a PyQt application
您可以在此找到它以供参考:
from IPython.zmq.ipkernel import IPKernelApp
from IPython.lib.kernel import find_connection_file
from IPython.frontend.qt.kernelmanager import QtKernelManager
from IPython.frontend.qt.console.rich_ipython_widget import RichIPythonWidget
from IPython.utils.traitlets import TraitError
from PySide import QtGui, QtCore
import atexit
def event_loop(kernel):
kernel.timer = QtCore.QTimer()
kernel.timer.timeout.connect(kernel.do_one_iteration)
kernel.timer.start(1000*kernel._poll_interval)
def default_kernel_app():
app = IPKernelApp.instance()
app.initialize(['python', '--pylab=qt', '--profile=plask'])
app.kernel.eventloop = event_loop
return app
def default_manager(kernel):
connection_file = find_connection_file(kernel.connection_file)
manager = QtKernelManager(connection_file=connection_file)
manager.load_connection_file()
manager.start_channels()
atexit.register(manager.cleanup_connection_file)
return manager
def console_widget(manager):
try: # Ipython v0.13
widget = RichIPythonWidget(gui_completion='droplist')
except TraitError: # IPython v0.12
widget = RichIPythonWidget(gui_completion=True)
widget.kernel_manager = manager
return widget
def terminal_widget(**kwargs):
kernel_app = default_kernel_app()
manager = default_manager(kernel_app)
widget = console_widget(manager)
# Update namespace
kernel_app.shell.user_ns.update(kwargs)
kernel_app.start()
return widget
# This simply opens qtconsole widged in a new window. But you can find embed it wherever you want
app = QtGui.QApplication([''])
widget = terminal_widget(testing=123)
widget.setWindowTitle("Your console")
widget.show()
app.exec_()