Question

目前我正在验证用户登录，所以使用程序将用户名和密码与signupform表进行比较，然后找到一个记录集值> 0（成功）或＆lt; 0（失败），但我不是很好在程序概念，我尝试了我的水平最好，但我无法解决这个，请帮助我。在此先感谢

我试过这个：

Create table signupform (username varchar(10), password varchar(10)); 
Insert into signupform values ('sampath','s96000');
Insert into signupform values ('yuvaraj','y96297');
select * from signupform;

// CREATE PROCEDURE for compare username and password
create procedure testing (@username varchar(10), @password varchar(10))
AS
BEGIN
select * from signupform where username = @username and password = @password
End;

Answer 1

我建议您创建功能：

create function testing(@username varchar(10), @password varchar(10))
RETURNS bit
BEGIN
   if EXISTS(select * from signupform where username = @username and password = @password)
   then
      return 1;
   else
      return 0; 
   end if;
end;

Answer 2

尝试检查用户表中是否存在某些login / pwd

if EXISTS(SELECT TOP 1 * FROM signupform WHERE username = @username AND password = @password)
begin

set @res = 1;
end

    select @res as valid
    return

Answer 3

您可以确保无论如何返回值，这样您就不必担心计数行

了

IF EXISTS(  
   SELECT *  
   FROM signupform  
   WHERE username = @username AND password = @password)  
BEGIN  
   SELECT 'Y'  
END  
ELSE  
BEGIN  
   SELECT 'N'  
END

或者做一个计数，但可能效率不高

SELECT COUNT(*)  
FROM signupform  
WHERE username = @username AND password = @password

Answer 4

试试这些SELECT语句：

SELECT UPPER(LEFT(@TypeName, 3)) into @TypeCode;
SELECT UPPER(LEFT(BranchName, 3)) into @Branch from tbl_erp_branches where BranchId=BranchIds;
-- SELECT UPPER(LEFT(AccountHeadName, 3)) into @Head from fin_erp_account_head where AccountHeadId=AccountHeadIds;
SELECT UPPER(LEFT(AccountHeadName, 3)) into @Head from fin_erp_account_head where AccountHeadId=AccountHeadIds;
SELECT UPPER(LEFT(CurrencyCode, 3)) into @Currency from tbl_erp_currency where CurrencyId=CurrencyIds;

如何使用MySQL中的过程验证用户登录？

4 个答案: