CursorIndexOutOfBoundsException请求索引0,大小为0

时间:2012-06-29 06:56:23

标签: android database sqlite cursor

我正在尝试从我的数据库的某一行获取文本。为此,我做了这个功能

public String getTranslation(long rowId) throws SQLException {    
    String str = null;
    Cursor mCursor = db.query(
        true, TABLE_LANGUAGE_FR, new String[] {
            KEY_ID_INTERFACE_TEXT, KEY_ITEM_NAME,KEY_FORM_LABEL_ID, KEY_FORM_RANK
        }, 
        KEY_FORM_LABEL_ID + "=" + rowId, null, null, null, null, null
    );

    if (mCursor != null) {
        mCursor.moveToFirst();
        str = mCursor.getString(mCursor.getColumnIndex(KEY_ITEM_NAME));
    }
    return str;
}

我称之为:

db = new DbAdapter(this);
db.createDatabase(); 
db.openDataBase();
String str = db.getTranslation(1706);

我的表格如下:

enter image description here

我收到此错误:

09:32:08.965    307 com.Orange  ERROR   AndroidRuntime  Caused by: android.database.CursorIndexOutOfBoundsException: Index 0 requested, with a size of 0
09:32:08.965    307 com.Orange  ERROR   AndroidRuntime      at android.database.AbstractCursor.checkPosition(AbstractCursor.java:580)
09:32:08.965    307 com.Orange  ERROR   AndroidRuntime      at android.database.AbstractWindowedCursor.checkPosition(AbstractWindowedCursor.java:214)
09:32:08.965    307 com.Orange  ERROR   AndroidRuntime      at android.database.AbstractWindowedCursor.getString(AbstractWindowedCursor.java:41)
09:32:08.965    307 com.Orange  ERROR   AndroidRuntime      at com.Orange.Database.DbAdapter.getTranslation(DbAdapter.java:141)
09:32:08.965    307 com.Orange  ERROR   AndroidRuntime      at com.Orange.Authentication.onCreate(Authentication.java:32)

为什么我收到此错误?我在这里做错了什么?

提前致谢。

3 个答案:

答案 0 :(得分:25)

看起来你有一个emtpy游标。不要检查它是否为空,请尝试检查

if(mCursor.getCount() > 0)
{
  //do stuff
}

尝试删除where条件,以确保在运行select语句时实际获取数据。 如果你仍然得不到任何结果,你的表名中可能会输入拼写错误,或者无法连接/创建数据库/表。

Cursor mCursor = db.query("sys_interface_text", new String[] {
       "id_interface_text", "item_name","form_label_id", "form_rank"}, 
               "form_label_id = 1706", null, null, null,
       null);

答案 1 :(得分:1)

尝试使用

while(cursor.moveToNext())
{
   if(cursor.isFirst())
   {
      //Your code goes here in your case
      return mCursor.getString(mCursor.getColumnIndex(KEY_ITEM_NAME));
   }
}
finaly
{
 if(mCursor!= null)
 {
   mCursor.close();
 }
}

答案 2 :(得分:0)

尝试更改此行

Cursor mCursor = db.query(true, TABLE_LANGUAGE_FR, new String[] {
           KEY_ID_INTERFACE_TEXT, KEY_ITEM_NAME,KEY_FORM_LABEL_ID, KEY_FORM_RANK}, 
                   KEY_FORM_LABEL_ID + "=" + rowId, null, null, null,
           null, null);

通过

Cursor mCursor = db.query(TABLE_LANGUAGE_FR, new String[] {
           KEY_ID_INTERFACE_TEXT, KEY_ITEM_NAME,KEY_FORM_LABEL_ID, KEY_FORM_RANK}, 
                   KEY_FORM_LABEL_ID + "=" + rowId, null, null, null,
           null);

并在条件

中添加此项
 return str;