我正在寻找
的内容str_split_whole_word($longString, x)
其中$longString
是句子的集合,x
是每行的字符长度。它可能相当长,我想基本上以数组的形式将它分成多行。
例如,
$longString = 'I like apple. You like oranges. We like fruit. I like meat, also.';
$lines = str_split_whole_word($longString, x);
$lines = Array(
[0] = 'I like apple. You'
[1] = 'like oranges. We'
[2] = and so on...
)
答案 0 :(得分:44)
最简单的解决方案是在新行上使用wordwrap()
和explode()
,如下所示:
$array = explode( "\n", wordwrap( $str, $x));
其中$x
是要包装字符串的字符数。
答案 1 :(得分:13)
此解决方案可确保创建行而不会破坏单词,使用wordwrap()将无法获得。
它将使用空间来爆炸字符串,然后使用foreach循环数组并创建行而不会破坏工作并使用$maxLineLength
定义的最大长度。下面是代码,我做了一些测试,它工作正常。
$longString = 'I like apple. You like oranges. We like fruit. I like meat, also.';
$arrayWords = explode(' ', $longString);
$maxLineLength = 18;
$currentLength = 0;
$index = 0;
foreach ($arrayWords as $word) {
// +1 because the word will receive back the space in the end that it loses in explode()
$wordLength = strlen($word) + 1;
if (($currentLength + $wordLength) <= $maxLineLength) {
$arrayOutput[$index] .= $word . ' ';
$currentLength += $wordLength;
} else {
$index += 1;
$currentLength = $wordLength;
$arrayOutput[$index] = $word;
}
}
答案 2 :(得分:10)
使用wordwrap()
插入换行符,然后explode()
插入这些换行符:
// Wrap at 15 characters
$x = 15;
$longString = 'I like apple. You like oranges. We like fruit. I like meat, also.';
$lines = explode("\n", wordwrap($longString, $x));
var_dump($lines);
array(6) {
[0]=>
string(13) "I like apple."
[1]=>
string(8) "You like"
[2]=>
string(11) "oranges. We"
[3]=>
string(13) "like fruit. I"
[4]=>
string(10) "like meat,"
[5]=>
string(5) "also."
}
答案 3 :(得分:1)
来自 Marcio simao 评论
的功能function explodeByStringLength($string,$maxLineLength)
{
if(!empty($string))
{
$arrayWords = explode(" ",$string);
if(count($arrayWords) > 1)
{
$maxLineLength;
$currentLength = 0;
foreach($arrayWords as $word)
{
$wordLength = strlen($word);
if( ( $currentLength + $wordLength ) <= $maxLineLength )
{
$currentLength += $wordLength;
$arrayOutput[] = $word;
}
else
{
break;
}
}
return implode(" ",$arrayOutput);
}
else
{
return $string;
}
}
else return $string;
}
答案 4 :(得分:1)
尝试此功能.......
<?php
/**
* trims text to a space then adds ellipses if desired
* @param string $input text to trim
* @param int $length in characters to trim to
* @param bool $ellipses if ellipses (...) are to be added
* @param bool $strip_html if html tags are to be stripped
* @param bool $strip_style if css style are to be stripped
* @return string
*/
function trim_text($input, $length, $ellipses = true, $strip_tag = true,$strip_style = true) {
//strip tags, if desired
if ($strip_tag) {
$input = strip_tags($input);
}
//strip tags, if desired
if ($strip_style) {
$input = preg_replace('/(<[^>]+) style=".*?"/i', '$1',$input);
}
if($length=='full')
{
$trimmed_text=$input;
}
else
{
//no need to trim, already shorter than trim length
if (strlen($input) <= $length) {
return $input;
}
//find last space within length
$last_space = strrpos(substr($input, 0, $length), ' ');
$trimmed_text = substr($input, 0, $last_space);
//add ellipses (...)
if ($ellipses) {
$trimmed_text .= '...';
}
}
return $trimmed_text;
}
?>
信用:http://www.ebrueggeman.com/blog/abbreviate-text-without-cutting-words-in-half
答案 5 :(得分:1)
仅需一个preg_
函数调用即可完成整个任务。
$maxLength
次之间的任何字符。\K
忘记/释放#1中匹配的字符。preg_
函数以排除通过用PREG_SPLIT_NO_EMPTY
在字符串位置的末尾分割而产生的空元素。代码:(Demo)
$longString = 'I like apple. You like oranges. We like fruit. I like meat, also.';
$maxLength = 18;
var_export(
preg_split("/.{0,{$maxLength}}\K(?:\s+|$)/", $longString, 0, PREG_SPLIT_NO_EMPTY)
);
输出:
array (
0 => 'I like apple. You',
1 => 'like oranges. We',
2 => 'like fruit. I like',
3 => 'meat, also.',
)
如果输入字符串可能包含换行符,则只需添加s
模式修饰符。
/.{0,{$maxLength}}\K(?:\s+|$)/s
(Demo)
答案 6 :(得分:0)
我的要求是每隔20个字符后使用不带断词的拆分文本字符串。使用wordwrap()在每20个字符后插入换行符,这就是我的操作方法。希望这对其他找到这种解决方案的人有所帮助。
$charactersLimit = 20;
$yourTextString = 'Lorem ipsum dolor sit amet, consectetuer adipiscing elit.';
$output = explode("\n", wordwrap($yourTextString, $charactersLimit));
输出如下:
Array
(
[0] => Lorem ipsum dolor
[1] => sit amet,
[2] => consectetuer
[3] => adipiscing elit.
)