我需要删除仅包含单个单词的引号,并将其保留在双字词周围。
... SO
“橘子”,“黄香蕉”,“红苹果”和
“黄香蕉”,“红苹果”,“橙子”
应该是这样的:
“黄香蕉”,“红苹果”,橙子
答案 0 :(得分:0)
如果你的列表没有正确格式化(缺少空格或额外的标点符号),那么快速去,这可行,但它不是最佳:)
您没有指定文本的位置或访问它的方式只是做了以下任何事情:)
Public Sub fixQuotes(ByVal Target As Range)
Dim Words() As String
Dim Word As String
Dim Index As Long
Dim Result As String
Words = Split(Target.Value, " ")
Result = ""
For Index = LBound(Words) To UBound(Words)
Word = Words(Index)
Word = Replace(Word, ",", "")
Word = Replace(Word, ".", "")
If Left(Word, 1) = Chr(34) And Right(Word, 1) = Chr(34) Then
Result = Result & Replace(Words(Index), Chr(34), "") & " "
Else
Result = Result & Words(Index) & " "
End If
Next Index
Target.Value = Result
End Sub
看了你的例子后,我发现前一个例子根本不会很好(它需要列表项之间的空格)
所以我做了一个新的:)
Public Function fixQuotes2(ByVal Text As String) As String
Dim Index As Integer
Dim Character As String
Dim Quote As Boolean
Dim A As Integer
Dim Result As String
Index = 1
Do
If Mid(Text, Index, 1) = Chr(34) And Index < Len(Text) Then
A = 1
Quote = False
Do
Character = Mid(Text, Index + A, 1)
If Character = " " Then
Quote = True
End If
If Character = Chr(34) Then
Exit Do
Else
If Index + 1 >= Len(Text) Then
Exit Do
Else
A = A + 1
End If
End If
Loop
If Quote = True Then
Result = Result & Mid(Text, Index, A + 1)
Else
Result = Result & Mid(Text, Index + 1, A - 1)
End If
Index = Index + A + 1
Else
If Index >= Len(Text) Then
Exit Do
Else
Result = Result & Mid(Text, Index, 1)
Index = Index + 1
End If
End If
Loop
fixQuotes2 = Result
End Function
这个可以用作工作表函数,与第一个不同。
注意:确保在尝试之前保存了您的资料! (制作时有几个无限循环:p)
Public Sub fixMacro()
ActiveCell.Value = fixQuotes2(CStr(ActiveCell.Value))
End Sub
将它与fixQuotes2一起添加,你将获得&#34; fixMacro&#34;在宏列表中,当您运行宏时,它将在活动单元格上运行该函数,并将其值替换为固定版本。
答案 1 :(得分:0)
Sub DeQuoteSingleWords()
Dim c As Range, arr, x
For Each c In Selection.Cells
arr = Split(Trim(c.Value), ",")
For x = LBound(arr) To UBound(arr)
arr(x) = Trim(arr(x))
If InStr(arr(x), " ") = 0 Then
arr(x) = Replace(arr(x), """", "")
End If
Next x
c.Offset(0, 1).Value = Join(arr, ", ")
Next c
End Sub