Question

我有一个要求。

鉴于Test1，Test2，我必须执行类似的操作。

像

这样的东西

select * from tblname where column_name like('Test1%','Test2%');

即。这些字符串以逗号分隔

我该如何解决这个问题？

这是在SQL SERVER 2005中。

先谢谢

Answer 1

您需要创建一个这样的SQL语句：

SELECT
    *
FROM
    tblname
WHERE
    column_name like 'Test1%'
    OR
    column_name like 'Test2%'

每个案例都需要一个OR

Answer 2

    declare @v varchar(50)
    declare @sql varchar(1000)
    declare @c int

    set @v = ltrim(rtrim(' An Gu an')) -- this is your search creteria
    set @sql = 'select * from tblname where '
    set @c = charindex(' ', @v)

    while @c > 0
        begin
           set @sql = @sql + 'column_name ' + ' like ''%' + 
                       left(@v,@c-1) +'%'' OR ';
            set @v = right(@v, len(@v)-@c)      
            set @c = charindex(' ', @v)
        end
    set @sql = @sql + ' column_name like ''%'+@v +'%'''

      --sql now contains
      --select * from tblname where 
      -- column_name  like '%An%' OR 
      -- column_name  like '%Gu%' OR  
      -- column_name like '%an%'

    exec( @sql)

Answer 3

Sql server 2005，试试这个

--Lookup Table
DECLARE @Values TABLE(
        Column_Name VARCHAR(MAX)
)

INSERT INTO @Values (Column_Name) SELECT 'A'
INSERT INTO @Values (Column_Name) SELECT 'B'
INSERT INTO @Values (Column_Name) SELECT 'ATADA'
INSERT INTO @Values (Column_Name) SELECT 'TADAA'
INSERT INTO @Values (Column_Name) SELECT 'Test123A'
INSERT INTO @Values (Column_Name) SELECT '1Test123A'

--Lookup string and delim
DECLARE @LookupString VARCHAR(MAX)
DECLARE @Delim VARCHAR(1)

SET @LookupString = 'Test1,Test2,TADA'
SET @Delim = ',';

--CREATE A LOOKUP TABLE FOR SPLIT STRINGS
WITH substrings (Val, Remainder) AS(
    SELECT  CASE WHEN CHARINDEX(@Delim,@LookupString) = 0 THEN @LookupString ELSE LEFT(@LookupString,CHARINDEX(@Delim,@LookupString)-1) END,
            CASE WHEN CHARINDEX(@Delim,@LookupString) = 0 THEN '' ELSE RIGHT(@LookupString,LEN(@LookupString) - CHARINDEX(@Delim,@LookupString)) END
    UNION ALL 
    SELECT  CASE WHEN CHARINDEX(@Delim,Remainder) = 0 THEN Remainder ELSE LEFT(Remainder,CHARINDEX(@Delim,Remainder)-1) END,
            CASE WHEN CHARINDEX(@Delim,Remainder) = 0 THEN '' ELSE RIGHT(Remainder,LEN(Remainder) - CHARINDEX(@Delim,Remainder)) END
    FROM substrings
    WHERE CHARINDEX(@Delim,Remainder) >= 0 AND Val != '' AND Remainder != ''
)
SELECT  v.Column_Name,
        substrings.Val
FROM    @Values v INNER JOIN
        substrings ON v.Column_Name LIKE substrings.Val + '%'

Answer 4

示例代码：

 declare @val varchar(100) set @val = '30,31,34,35,24,16'

PRINT REPLACE((','+@val),',','%'' OR MAQL LIKE ''%') + '%'''

SQL SERVER 2005中的多个搜索选项

4 个答案: