Ruby代码是:
a = []
h = {}
2.times.each do |i|
%w(a b c).each do |x|
h[x] = x + i.to_s
end
a << h
end
结果是:
a = [{"c"=>"c1", "b"=>"b1", "a"=>"a1"}, {"c"=>"c1", "b"=>"b1", "a"=>"a1"}]
但我希望结果是:
a = [{"c"=>"c0", "b"=>"b0", "a"=>"a0"}, {"c"=>"c1", "b"=>"b1", "a"=>"a1"}]
谁可以帮助我.thx
答案 0 :(得分:2)
在a << h
之后,您必须h = {}
。这是因为您要为h分配一个新对象,以便它不会覆盖以前的值。
答案 1 :(得分:0)
[补充答案] 您熟悉functional programming的原则吗?
(0..1).map { |n| Hash[("a".."c").map { |c| [c, "#{c}#{n}"] }] }
#=> {"a"=>"a0", "b"=>"b0", "c"=>"c0"}, {"a"=>"a1", "b"=>"b1", "c"=>"c1"}]