使用re.search python进行不平衡的括号错误

时间:2012-06-28 02:24:26

标签: python regex parentheses

我有一个我想循环的列表(对于trim中的trimtemp),看看它是否在给定的字符串(modeltrim)中有任何匹配。代码在大多数情况下运行正常但是,它偶尔会出现以下错误:

Traceback (most recent call last):
  File "/home/hostadl/PricesFinal.py", line 318, in <module>
    main()
  File "/home/hostadl/PricesFinal.py", line 215, in main
    match = re.search(r'{0}'.format(trimtemp), modeltrim, re.IGNORECASE)
  File "/usr/local/lib/python3.2/re.py", line 158, in search
    return _compile(pattern, flags).search(string)
  File "/usr/local/lib/python3.2/re.py", line 256, in _compile
    return _compile_typed(type(pattern), pattern, flags)
  File "/usr/local/lib/python3.2/functools.py", line 180, in wrapper
    result = user_function(*args, **kwds)
  File "/usr/local/lib/python3.2/re.py", line 268, in _compile_typed
    return sre_compile.compile(pattern, flags)
  File "/usr/local/lib/python3.2/sre_compile.py", line 491, in compile
    p = sre_parse.parse(p, flags)
  File "/usr/local/lib/python3.2/sre_parse.py", line 692, in parse
    p = _parse_sub(source, pattern, 0)
  File "/usr/local/lib/python3.2/sre_parse.py", line 315, in _parse_sub
    itemsappend(_parse(source, state))
  File "/usr/local/lib/python3.2/sre_parse.py", line 642, in _parse
    raise error("unbalanced parenthesis")
sre_constants.error: unbalanced parenthesis

非常感谢您的帮助!

1 个答案:

答案 0 :(得分:2)

此行似乎是问题

match = re.search(r'{0}'.format(trimtemp), modeltrim, re.IGNORECASE)

您应该查看format(trimtemp)包含的内容。也许只需添加一个

print format(trimtemp)

之前就行了。可能它包含(),它们对re具有重要意义。或许re.escape(format(trimtemp))就是你所需要的